To determine which number is divisible by 3, 6, and 9, we need to check if the sum of the digits of each number is divisible by 3. For 369: 3+6+9 = 18, which is divisible by 3, 6, and 9. Therefore, 369 is divisible by 3, 6, and 9. For 246: 2+4+6 = 12, which is divisible by 3 but not by 6 or 9. Therefore, 246 is divisible by 3 but not by 6 or 9. For 468: 4+6+8 = 18, which is divisible by 3, 6, and 9. Therefore, 468 is divisible by 3, 6, and 9. For 429: 4+2+9 = 15, which is divisible by 3 but not by 6 or 9. Therefore, 429 is divisible by 3 but not by 6 or 9. Therefore, the numbers 369 and 468 are divisible by 3, 6, and 9.
104 792 468 976 552
Yes, 468 ends with an even number (ex: 0,2,4,6,8 etc) so it is divisible by 2. The answer is 234.
234, 468, 702 and so on.
936 is one of an infinite number of numbers
To determine which number is divisible by 3, 6, and 9, we need to check if the sum of the digits of each number is divisible by 3. For 369: 3+6+9 = 18, which is divisible by 3, 6, and 9. Therefore, 369 is divisible by 3, 6, and 9. For 246: 2+4+6 = 12, which is divisible by 3 but not by 6 or 9. Therefore, 246 is divisible by 3 but not by 6 or 9. For 468: 4+6+8 = 18, which is divisible by 3, 6, and 9. Therefore, 468 is divisible by 3, 6, and 9. For 429: 4+2+9 = 15, which is divisible by 3 but not by 6 or 9. Therefore, 429 is divisible by 3 but not by 6 or 9. Therefore, the numbers 369 and 468 are divisible by 3, 6, and 9.
468 is divisible by all of its factors, 1, 2, 3, 4, 6, 9, 12, 13, 18, 26, 36, 39, 52, 78, 117, 156, 234, and 468.
104 792 468 976 552
2 and 3 yes, 5 no.
Oh, dude, like totally! 468 is divisible by 4 because when you divide 468 by 4, you get 117, which is a whole number without any remainders. So yeah, 468 is totally cool with being divided by 4.
Yes, 468 ends with an even number (ex: 0,2,4,6,8 etc) so it is divisible by 2. The answer is 234.
Unfortunately, the least common multiple in this case is rather large. 468 is the smallest number that is divisible by both 13 and 36. 36 is already divisible by 3 so 3 does not matter for this problem. 13 is prime and is not a factor of 36 so the first multiple of 13 that is divisible by 36 is 13 * 36 which is 468.
The infinite set of numbers characterised by 468*k where k is an integer.
468
234, 468, 702 and so on.
936 is one of an infinite number of numbers
The number is 468.