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Yes. This is easy to prove; in the following, I'll use "^" for powers. Let the complex number be (a + bi), then its conjugate, by definition, is (a - bi). Multiplying them, you get a^2 + abi - abi + bi^2 = a^2 + bi^2 = a^2 - b^2 (since i^2 = -1).Update: One interesting, and quite useful, property is that the product of the complex number and its conjugate is equal to the square of the absolute value of the complex number.

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7y ago
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7y ago

if z = x + iy (x and y are both real) then its conjuguate is x - iy, their product is

( x + iy ) ( x - iy ) = x^2 -xiy + xiy - i^2 y ^2 = x^2 + y ^2, then it's a real number

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7y ago

Yes.

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Q: Is The product of a complex number and its conjugate is a real number.?
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What is the relationship between a complex number and its conjugate?

When a complex number is multiplied by its conjugate, the product is a real number and the imaginary number disappears.


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Graphically, the conjugate of a complex number is its reflection on the real axis.


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Complex numbers form: a + bi where a and b are real numbers. The conjugate of a + bi is a - bi If you multiply a complex number by its conjugate, the product will be a real number, such as (a + bi)(a - bi) = a2 - (bi)2 = a2 - b2i2 = a2 - b2(-1) = a2 + b2


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Not necessarily. It can be wholly imaginary.For example, 1 + i actually has two complex conjugates. Most schools will teach you that the complex conjugate is 1 - i. However, -1 + i is also a conjugate for 1 + i. (Their product is -1 times the product of the "normal" conjugate pair).The sum of 1 + i and -1 + i = 2i


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What is self conjugate of complex number?

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