No, not necessarily! In fact, much of the time, the length of an object usually longer the width of it. For examples, consider what you know just by seeing them of these LxW objects:
width=5 length=12
8 and 6
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
49
3 and 7
Length is how long or tall something is and width is how wide it is. It's sometimes fairly arbitrary which direction is the length and which is the width. But usually it's more natural to let the length be the longer direction. It's also common to talk about "width and height" instead of "length and width." In this case, height is usually vertical, and width horizontal.
A square has width and height. Width is the horizontal line, height is the vertical line. This is a two-dimensional object and has an area.A cube is a square with one more dimension, length, which makes it a three dimensional object. As a three-dimensional object, it no longer has an area, but now has volume.To find the area of a cube (a three-dimensional object), one must multiply three dimensions (length, width, and height) to obtain the volume of the cube.
Perimeter = 2 lengths and 2 widths In your case length + width = 25cm If length is 5cm more than width then length = 15cm and width = 10cm
width=5 length=12
Length = 20 m and width = 9 m
You don't have enough information to find the exact length of the width, but the width has to be less then 7.5 if it smaller then the length.
the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle
OK so we have two formulas: Length = width + 5 (since legth is 5 more than width) length + width + length + width = perimeter= 82 (form. for perm.) so we can replace every instance of "length" with "width + 5" since they are the same. width + 5 + width + width + 5 + width = 82 4xwidth + 10 = 82 4X width = 72 width = 23 so now go back and replace "width" with 23. length = 23 + 5 length = 28 There you go.
Let the width of rectangle is w cm (Length is 12 cm more) so length is w + 12 Perimeter = 16 times of width 2 (length + width) = 16 * width Rest of the homework, do yourself.
The width could be virtually anything. If you are wanting to find out how to calculate width, you need to have more information in addition to length.
The perimeter of a standard- sized rectangular rug is 94 ft. the length is 3 ft more than the width. Find the length and the width.
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.