The equation N-6=2 is a math problem. The answer to this math problem would be N=4.
E
n 6 22
-4
2+n-3 = 6 n = 6+3-2 n= 7
-6 = n/2 - 10 4 = n/2 2 = n
5n + 2 = 5 x n + 2 So, when n = 6, that is 5 x 6 + 2 = 30 + 2 = 32.
6 < n/2
-4
2+n-3 = 6 n = 6+3-2 n= 7
2 plus 2 plus n equals 6 n equaling 2
-6 = n/2 - 10 4 = n/2 2 = n
for the equation: n - 6 = 2, add 6 to both sides of the equationn - 6 + 6 = 2 + 6 --> n = 8
8
n+6 = 2(n/2+3) <=> n+6 = 2(n/2)+2(3) <=> n+6 = n+6. Any number you put in for n will make this equation true. It is an identity, and has an infinite number of solutions.
n/2 + 6 = n/3 so 6 = n/3 - n/2 = 2n/6 - 3n/6 = -n/6 and so n = -36
8
5n + 2 = 5 x n + 2 So, when n = 6, that is 5 x 6 + 2 = 30 + 2 = 32.
m + n = 6 mn = 24 Hence m = 24/n Substitute 24/n + n = 6 Multiply through by 'n' 24 + n^2 = 6n n^2 - 6n + 24 = -0 This does NOT factor so apply the Quadratic Equation. n ={--6+/- sqrt[(-6)^2 - 4(1)(24)]} / 2(1) n = {6 +/- sqrt[36 - 96]} / 2 n = {6 +/- sqrt[-60]} / 2 We now move into imaginary numbers, designated by 'i' (= sqrt(-1) . Hence n = {6 +/- i sqrt(60)} / 2 n = {6 +/- i(7.74596...)} / 2 n = 3 +/- 3.87298... i Hence n = 3 + 3.87298...i & 3 - 3.87298 ... i
24