8
10,11,12,13,14 or 8,10,12,14,16
The sequence 4n + 7 represents a linear sequence where n is the position in the sequence. To find the first five terms, substitute n with 1, 2, 3, 4, and 5 respectively. Thus, the first five terms are 11, 15, 19, 23, and 27.
Suppose the first term is a, the second is a+r and the nth is a+(n-1)r. Then the sum of the first five = 5a + 10r = 85 and the sum of the first six = 6a + 15r = 123 Solving these simultaneous equations, a = 3 and r = 7 So the first four terms are: 3, 10, 17 and 24
x is the first term and d is the difference then x + 3d = 15 and sum of first five terms isx + (x+d) + (x+2d) + (x+3d) + (x+4d)so 5x + 10d = 55 ie x + 2d = 11As x + 3d = 15, d = 4 and x = 3,giving the five terms as 3, 7, 11, 15 and 19
5
It could be any number of your choice. Pick a number and I can find you a quartic (power 4) polynomial which will give the above four and your choice as the first five terms. But the simplest cubic rule is Un = (n3 - 6n2 + 8)/3 for n = 1, 2, 3, ... which gives U5 = 5
All but John Adams served two terms. The total of the first five was nine terms or 36 years (almost - Washington's first term was about an month short.)
4 = -5n + 6n2 if you want to solve for n: 6n2 - 5n - 4 = 0 (3n - 4)(2n + 1) = 0 3n - 4 = 0, n = 4/3 2n + 1 = 0, n = -1/2 n = {-1/2, 4/3}
In mathematics, the "first five terms" typically refers to the initial five elements of a sequence or series. For example, in an arithmetic sequence, if the first term is 2 and the common difference is 3, the first five terms would be 2, 5, 8, 11, and 14. This concept is often used to analyze patterns, behaviors, or properties of sequences.
2n(3n + 8)
7
6n2+6n+1
2,1,0 is th sequence of its terms
The expression "n plus 3" can be represented as ( n + 3 ). To find the first five terms, we can substitute the values ( n = 1, 2, 3, 4, ) and ( 5 ) into the expression. The first five terms are: ( 1 + 3 = 4 ) ( 2 + 3 = 5 ) ( 3 + 3 = 6 ) ( 4 + 3 = 7 ) ( 5 + 3 = 8 ) Thus, the first five terms are 4, 5, 6, 7, and 8.
6n2
no clue
What does N equal? Well to solve the problem you would do N+7x1, N+7x2, N+7x 3, N+7x4, N+7x5 to figure out the first five terms.