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What is the first five terms of 6n-2?
8
What is the sum of one half of a number and 6 equals one third of the number what is the number?
n/2 + 6 = n/3 so 6 = n/3 - n/2 = 2n/6 - 3n/6 = -n/6 and so n = -36
What is the sum of the first n positive integer?
(n/2) times (n + 1) eg for first 6 integers n = 6 and you have 6/2 x 6 + 1 = 3 x 7 = 21 which is correct.
What is 3n plus 6 equals 18?
3n+6=18 n+2=6 n=4
What is the algebraic expression for 3 6 10 15?
t(n) = (n+1)*(n+2)/2 where n = 1 ,2, 3, ...
What is n plus 2 equals -6?
-4
What is n in this equation 2 plus n-3 equals 6?
2+n-3 = 6 n = 6+3-2 n= 7
What is the answer to -6 equals n divided by 2 minus 10?
-6 = n/2 - 10 4 = n/2 2 = n
How do you get your variable alone in n - 6 equals 2?
for the equation: n - 6 = 2, add 6 to both sides of the equationn - 6 + 6 = 2 + 6 --> n = 8
What is the first five terms of 6n-2?
8
N 6 2?
The equation N-6=2 is a math problem. The answer to this math problem would be N=4.
What is the sum of one half of a number and 6 equals one third of the number what is the number?
n/2 + 6 = n/3 so 6 = n/3 - n/2 = 2n/6 - 3n/6 = -n/6 and so n = -36
What is the sum of a number and 6 multiplied by -2?
8
If n equals 6 then what is the value of 5n plus 2?
5n + 2 = 5 x n + 2 So, when n = 6, that is 5 x 6 + 2 = 30 + 2 = 32.
What two numbers multiply to 8 and add to -6?
Let the numbers be 'm' & 'n' Hence mn = 8 m + n = -6 m = 8/n Substitute 8/n + n = -6 Multiply through by 'n' 8 + n^(2) = -6n n^(2) + 6n + 8 = 0 Factor (n + 4 )(n + 2) = 0 Hence n = -4 & n = -2
What is the product of 8 and the sum of 6?
mn = 8 ( Product) m + n = 6 (Sum) Hence m = 6 - n Substitute (6 -n)n = 8 Multiply out the brackets 6n - n^(2) = 8 n^(2) - 6n + 8 = 0 It is now in quadratic form and will factor Hence ((n - 2)(n - 4) = 0 n = 2 & n = 4 So '2' & '4' are the two numbers. Verification 2 + 4 = 6 2 x 4 = 8
How do you write 6 less than half of n?
6 < n/2
