The reason that coin-flipping came to be used as a fair mechanism for making decisions is that the chance of either outcome is assumed to be 50%, so each participant is willing to trust the fate of his personal preference to the supposedly unbiased coin.
In reality, since the material in a coin is not symmetrically distributed, the probability of the two possible outcomes is not exactly equal, though I don't remember which way it leans statistically.
In any case, let's say that you have a fair, honest, balanced coin, with odds of exactly 50-50. That tells you that if you flipped the coin an infinite number of times, half would land on heads and half would land on tails. You still could not predict what the outcome of 60 flips would be. Even if the first 59 all landed on heads, the probability on the 60th toss would still be 50-50.
The probability that the coin will land on heads each time is 1/2. (1/2) to the tenth power is 1/1024. This is the probability that the coin will not land on heads. Subtract it from one to get the probability that it will : 1-(1/1024)There is a 1023/1024 or about 99.90234% chance that the coin will land on heads at least once.(There is a 1/1024 chance that the coin will land on heads all four times.)
Since it is a fair coin, the probability is 0.5
About a 1 in 16 chance of getting a coin to land on heads 4 times in a row.
1/8
We have no way of knowing the probability of any given person flipping any given coin at any given time. But for any two flips of an honest coin, the probability that both are tails is 25% . (1/4, or 3 to 1 against)
30 times because it landed on heads 20 times, but he flipped the coin 50 times. 20+30=50.
The probability of a fair coin landing heads up is always 0.5, regardless of previous outcomes. Each coin flip is an independent event, so the outcome of the previous flips does not affect the outcome of the next flip. Therefore, the probability of the coin landing heads up on the next flip is still 0.5.
The probability of a fair coin to land head is 1/2. Since for 4 flips it must land heads each time, the probability of 4 heads is 1/2 * 1/2 * 1/2 * 1/2 = 1/16.
A fair coin would be expected to land on heads 10 times on average.
The probability that the coin will land on heads each time is 1/2. (1/2) to the tenth power is 1/1024. This is the probability that the coin will not land on heads. Subtract it from one to get the probability that it will : 1-(1/1024)There is a 1023/1024 or about 99.90234% chance that the coin will land on heads at least once.(There is a 1/1024 chance that the coin will land on heads all four times.)
Since it is a fair coin, the probability is 0.5
A fair coin would be expected to land on heads 75 times.
It could land on heads any number of times between zero and 150.The most probable result, if the coin is honest and balanced, is 75 times.
This is a probability question. Probabilities are calculated with this simple equation: Chances of Success / [Chances of Success + Chances of Failure (or Total Chances)] If I flip a coin, there is one chance that it will land on heads and one chance it will land on tails. If success = landing on heads, then: Chances of Success = 1 Chances of Failure = 1 Total Chances = 2 Thus the probability that a coin will land on heads on one flip is 1/2 = .5 = 50 percent. (Note that probability can never be higher than 100 percent. If you get greater than 100 you did the problem incorrectly) Your question is unclear whether you mean the probability that a coin will land on head on any of 8 flips or all of 8 flips. To calculate either you could write out all the possible outcomes of the flips (for example: heads-heads-tails-tails-heads-tails-heads-heads) but that would take forvever. Luckily, because the outcome of one coin flip does not affect the next flip you can calculate the total probability my multiplying the probabilities of each individual outcome. For example: Probability That All 8 Flips Are Heads = Prob. Flip 1 is Heads * Prob. Flip 2 is Heads * Prob. Flip 3 is Heads...and so on Since we know that the probability of getting heads on any one flips is .5: Probability That All 8 Flips Are Heads = .5 * .5 * .5 * .5 * .5 * .5 * .5 * .5 (or .58) Probability That All 8 Flips Are Heads = .00391 or .391 percent. The probability that you will flip a heads on any of flips is similar, but instead of thinking about what is the possiblity of success, it is easier to approach it in another way. The is only one case where you will not a heads on any coin toss. That is if every outcome was tails. The probability of that occurring is the same as the probability of getting a heads on every toss because the probability of getting a heads or tails on any one toss is 50 percent. (If this does not make sense redo the problem above with tails instead of heads and see if your answer changes.) However this is the probability of FAILURE not success. This is where another probability formula comes into play: Probability of Success + Probability of Failure = 1 We know the probability of failure in this case is .00391 so: Probability of Success + .00391 = 1 Probability of Success = .9961 or 99.61 percent. Therefore, the probability of flipping a heads at least once during 8 coin flips is 99.61 percent. The probability of flipping a heads every time during 8 coin flips is .391 percent.
About a 1 in 16 chance of getting a coin to land on heads 4 times in a row.
1/2 or 0.5
1/8