Total of 6m north and 1m west. Using Pythagoras that's sqrt(36+4) miles in total at an angle whose tangent is 1/6, west of north.
80
To find the total displacement, we calculate the net movement in the north-south direction. The child walks 4 m south and then 5 m south, totaling 9 m south. They then walk 2 m north and 5 m north, totaling 7 m north. The net displacement is 9 m south - 7 m north = 2 m south.
Your displacement is 20 metres.
20 yards
To determine the displacement of the walker, we can use the Pythagorean theorem. The walker travels 4 km east and 3 km north, forming a right triangle with these two legs. The displacement (d) is the hypotenuse, calculated as ( d = \sqrt{(4^2 + 3^2)} = \sqrt{16 + 9} = \sqrt{25} = 5 ) km. Therefore, the displacement of the walker is 5 km in a direction northeast.
80
If Meg walks 5 blocks south, then turns around and walks 8 blocks back, her displacement is 3 blocks.
zero
5 blocks
The total displacement of the dog from the starting point can be calculated by finding the net displacement, which is the difference between the distances moved in each direction. In this case, the net displacement would be 6m north - 4m south, resulting in a total displacement of 2m north.
The answer is 80 because 100-30+10 is 80.
Sarah's total displacement can be found using the Pythagorean theorem. The horizontal displacement is 20 yards east, and the vertical displacement is 50 yards north minus 50 yards south, which equals 0. This means her total displacement is the square root of (20^2 + 0^2) = 20 yards.
2 m south
Your displacement is 20 metres.
If a person walks 10 meters north and then walks 10 meters south, their total displacement would be zero since they would end up back where they started.
20
20 yards