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What is the total displacement of a child who walks 4m south 2m north 5m south and 5m north?
To find the total displacement, we need to calculate the net movement in the north-south direction. The child walks 4m south and 5m south, totaling 9m south, and then walks 2m north and 5m north, totaling 7m north. The net displacement is 9m south - 7m north = 2m south. Therefore, the total displacement of the child is 2m south.
Meg walks 5 blocks south and then turns around and walks 8 blocks back to the north. the distance that she walks is 13 blocks. what is her displacement?
Meg's displacement is the straight-line distance from her starting point to her ending point. She walks 5 blocks south and then returns 8 blocks north, resulting in a net movement of 3 blocks north from her original position. Therefore, her displacement is 3 blocks north.
Mike walks 100 meters north then walks 30 meters south After this he walks another 10 meters north What is the magnitude of his total displacement during this walk in meters?
80
What is the total displacement of a child who walks 4 m south 2 m north 5 m south 5 m north?
To find the total displacement, we calculate the net movement in the north-south direction. The child walks 4 m south and then 5 m south, totaling 9 m south. They then walk 2 m north and 5 m north, totaling 7 m north. The net displacement is 9 m south - 7 m north = 2 m south.
What is the total displacement of a student who walks 3 blocks east 2 blocks north 1 block westand then 2 blocks south?
To calculate the total displacement, we can break down the student's movements into net east-west and north-south components. The student walks 3 blocks east, 1 block west (net 2 blocks east), and 2 blocks north, then 2 blocks south (net 0 blocks north). Therefore, the total displacement is 2 blocks east, resulting in a final displacement of 2 blocks east.
What is the total displacement of a child who walks 4m south 2m north 5m south and 5m north?
To find the total displacement, we need to calculate the net movement in the north-south direction. The child walks 4m south and 5m south, totaling 9m south, and then walks 2m north and 5m north, totaling 7m north. The net displacement is 9m south - 7m north = 2m south. Therefore, the total displacement of the child is 2m south.
Meg walks 5 blocks south and then turns around and walks 8 blocks back to the north. the distance that she walks is 13 blocks. what is her displacement?
Meg's displacement is the straight-line distance from her starting point to her ending point. She walks 5 blocks south and then returns 8 blocks north, resulting in a net movement of 3 blocks north from her original position. Therefore, her displacement is 3 blocks north.
Mike walks 100 meters north then walks 30 meters south After this he walks another 10 meters north What is the magnitude of his total displacement during this walk in meters?
80
Meg walks 5 blocks south and then turns around and walks 8 blocks back to the north the distance she walks is 13 blocks what is her displacement?
If Meg walks 5 blocks south, then turns around and walks 8 blocks back, her displacement is 3 blocks.
A boy first walks 120 meters north then turns around and walks 120 meters south his total displacement is?
zero
If a person walks 3 blocks East and 4 blocks North what is the displacement of the person?
5 blocks
A dog walks 6m north 4m south What is the total displcement of the dog from the starting point?
The total displacement of the dog from the starting point can be calculated by finding the net displacement, which is the difference between the distances moved in each direction. In this case, the net displacement would be 6m north - 4m south, resulting in a total displacement of 2m north.
Mike walks 100 meters north then walks 30 meters south. After this he walks another 10 meters north. What is the magnitude of his total displacement during this walk in meters?
The answer is 80 because 100-30+10 is 80.
What is the total displacement of a child who walks 4 m south 2 m north 5 m south 5 m north?
To find the total displacement, we calculate the net movement in the north-south direction. The child walks 4 m south and then 5 m south, totaling 9 m south. They then walk 2 m north and 5 m north, totaling 7 m north. The net displacement is 9 m south - 7 m north = 2 m south.
Sarah walks part way around around a swimming pool She walks 50 yards north then 20 yards east and 50 yards south The magnitude of her total displacement during the walk is how many yards?
Sarah's total displacement can be found using the Pythagorean theorem. The horizontal displacement is 20 yards east, and the vertical displacement is 50 yards north minus 50 yards south, which equals 0. This means her total displacement is the square root of (20^2 + 0^2) = 20 yards.
What is the total displacement of a student who walks 3 blocks east 2 blocks north 1 block westand then 2 blocks south?
To calculate the total displacement, we can break down the student's movements into net east-west and north-south components. The student walks 3 blocks east, 1 block west (net 2 blocks east), and 2 blocks north, then 2 blocks south (net 0 blocks north). Therefore, the total displacement is 2 blocks east, resulting in a final displacement of 2 blocks east.
What is the total displacement of a child who walks 4 m South 2 m North 5 m South and 5 m North?
2 m south
