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What is the sum of mA and m B?
It is mA + mB
How do you prove that the exterior angle of a triangle is equal to the sum of the two opposite interior angles?
Assume a triangle ABC with a line AB (containing the side AB) with external angle D which is formed when line AB and line segment AC intersect. We are asked to prove that the external angle D is equal to the sum of the two interior angles B and C. Angles A and D are supplementary angles (they sum to 180 degrees) because they are linear angles (both together make a straight line, or a 180 degree angle). This means: m<A + m<D = 180 degrees. m<A = 180 deg - m<D Then because A, B, and C are the three angles in a triange: m<A + m<B + m<C = 180 deg m<A = 180 deg - m<B - m<C By substituting 180 deg - m<D in for m<A in the above equation we get: 180 deg - m<D = 180 deg - m<B - m<C Subtract 180 deg from each side: -m<D = -m<B - m<C Multiply both sides by -1 m<D = m<B + m<C Which proves that the measure of the external angle D is equal to the sum of the two opposite interior angles B and C for any given triangle. wow. that's a lot. lol.
What is the sum of b and 5?
(b+5)
What is the sum and difference of the same two terms?
Assuming that a and b are two non-negative numbers, then their sum is a + b and the difference is |a - b|.
What 9 m b in b?
gdafjtbika
