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What is the sum of mA and m B?
It is mA + mB
How do you prove that the exterior angle of a triangle is equal to the sum of the two opposite interior angles?
Assume a triangle ABC with a line AB (containing the side AB) with external angle D which is formed when line AB and line segment AC intersect. We are asked to prove that the external angle D is equal to the sum of the two interior angles B and C. Angles A and D are supplementary angles (they sum to 180 degrees) because they are linear angles (both together make a straight line, or a 180 degree angle). This means: m<A + m<D = 180 degrees. m<A = 180 deg - m<D Then because A, B, and C are the three angles in a triange: m<A + m<B + m<C = 180 deg m<A = 180 deg - m<B - m<C By substituting 180 deg - m<D in for m<A in the above equation we get: 180 deg - m<D = 180 deg - m<B - m<C Subtract 180 deg from each side: -m<D = -m<B - m<C Multiply both sides by -1 m<D = m<B + m<C Which proves that the measure of the external angle D is equal to the sum of the two opposite interior angles B and C for any given triangle. wow. that's a lot. lol.
What is the sum of b and 5?
(b+5)
What 9 m b in b?
gdafjtbika
What is the sum and difference of the same two terms?
Assuming that a and b are two non-negative numbers, then their sum is a + b and the difference is |a - b|.
What is the sum of mA and m B?
It is mA + mB
The sum of 38 and m?
Sum = 38 + M
How do you prove that the exterior angle of a triangle is equal to the sum of the two opposite interior angles?
Assume a triangle ABC with a line AB (containing the side AB) with external angle D which is formed when line AB and line segment AC intersect. We are asked to prove that the external angle D is equal to the sum of the two interior angles B and C. Angles A and D are supplementary angles (they sum to 180 degrees) because they are linear angles (both together make a straight line, or a 180 degree angle). This means: m<A + m<D = 180 degrees. m<A = 180 deg - m<D Then because A, B, and C are the three angles in a triange: m<A + m<B + m<C = 180 deg m<A = 180 deg - m<B - m<C By substituting 180 deg - m<D in for m<A in the above equation we get: 180 deg - m<D = 180 deg - m<B - m<C Subtract 180 deg from each side: -m<D = -m<B - m<C Multiply both sides by -1 m<D = m<B + m<C Which proves that the measure of the external angle D is equal to the sum of the two opposite interior angles B and C for any given triangle. wow. that's a lot. lol.
The sum of 3 times m and n?
the sum of 3 times m and n
what id the sum of m and 6?
The sum of "m" and 6 is "m + 6".
What about nested for loop?
Possible. Example: void mat_mul (int m, int n, int l, const int **a, const int **b, int **c) { int i, j, k; double sum; for (i=0; i<m; ++i) { for (j=0; j<l; ++j) { sum= 0; for (k=0; k<n; ++k) { sum += a[i][k] * b[k][j]; } c[i][j]= sum; } }
The sum of two numbers is 12. The sum of the squares of the same two numbers is 90. What are the two numbers?
We get a system of equations: a+b=12 a2+b2=90. Replace 12-a for b, and we get: a2+(12-a)2=90 2a2-24a+144=90 2a2-24a+54=0 a2-12a+27=0 a1=9 a2=3 Because of symmetry, we get two equivalent solutions: a=9, b=3 or a=3,b=9
Write a c program that multiplies two numbers by repeated subtraction?
int mul (int a, int b) { int sum= 0; for (; b>0; --b) sum -= -a; for (; b<0; ++b) sum -= a; return sum; }
The sum of m and 9?
the sum of m and 9 is 9+m
What is the sum Of?
The sum of is the total of everything being summed; the sum total. Thus the sum of a, b and c is therefore a + b + c.
Why is the sum of an even and odd number alsways odd?
A number a is even if there exists an integer n such that a = 2n A number b is odd if there exists an integer m such that b = 2m + 1. So: a+b = (2n) + (2m +1) = 2 (n+m) + 1 Since n and m are integers, n+m is also an integer. So a+b satisfies the definition of an odd number.
How do you write the sum of b and 8?
The sum of b and 8 would be written b+8 or 8+b(commutative property of addition)
