To find all possible numbers using the digits 3, 5, 6, and 1, we can use the concept of permutations. There are 4 digits available, so there are 4 factorial (4!) ways to arrange them, which equals 24 possible combinations. This means there are 24 different numbers that can be formed using the digits 3, 5, 6, and 1.
Total number of possible 3-digit numbers = 9!x10!10!
7
Yes, it is. 5/1 equals 5.
Using the formula n!/r!(n-r)! where n is the number of possible numbers and r is the number of numbers chosen, there are 13983816 combinations of six numbers between 1 and 49 inclusive.
Impossible, as there are not enough numbers to cover all squares.
Total number of possible 3-digit numbers = 9!x10!10!
7
One possible pair of numbers is 1 and 60.
Yes, it is. 5/1 equals 5.
The four numbers that can be used in combinations or differences to make all numbers from 1 to 30 are 1, 2, 4, and 8. These numbers are powers of 2, which allows for the creation of all numbers from 1 to 30 through various combinations and differences. By using these four numbers strategically, one can generate any integer between 1 and 30.
Using the formula n!/r!(n-r)! where n is the number of possible numbers and r is the number of numbers chosen, there are 13983816 combinations of six numbers between 1 and 49 inclusive.
Using various mathematical techniques, this is possible.
Impossible, as there are not enough numbers to cover all squares.
Just 1.
The four digits can be used to produce infinitely many different numbers if repetition is permitted. Without repetition, there are 24 possible numbers. A lot more can be produced if the numbers are combined using binary oprations, fore example, 19 * 8/4 = 19*2 = 38.
46
The greatest possible number is 888... (repeating).