The odds of getting 100 percent on a 10 question multiple choice test with 2 possible answers for each question can be calculated using the probability formula. Since there are 2 options for each question, the probability of getting a question right by guessing is 1/2 or 0.5. To calculate the probability of getting all 10 questions correct by guessing, you would multiply the probability of getting each question right (0.5) by itself 10 times, resulting in a probability of (0.5)^10, which is approximately 0.0009765625 or 0.09765625%.
The probability of getting both answers correct is one chance in nine (0.1111+). There are three possible answers for each question, so there is a 1/3 chance of getting the correct answer to one question. To get the correct answer for both questions, the chances are 1/3 x 1/3 or 1/9.
It is 0.0033
Let us say that for each question, there are n multiple choices. If this is true and false, then n=2. The chance of getting a right answer is 1/n and wrong answer (n-1)/n. I will define p as getting a wrong answer one time (p = (n-1)/n so the probability of 20 wrong answers is p20. Now for n = 4, p=0.75 and the chance of 20 wrong answers in a row is: (0.75)20= 0.0032 or 0.32%.
That depends on how many questions there are, how many choices are listed for each question, and whether any obviously-stupid answers are included among the choices. If any of those factors changes, then the probability changes. One thing we can guarantee, however, even without knowing any of these factors: If you have studied the subject and know the material, then your probability of getting correct answers increases dramatically.
49.999 (repeater)% * * * * * It is not possible to answer the question without knowing what the experiment or the event space is.
If you can recognize one or more of the possible answers on the SAT multiple choice as clearly NOT being correct, but you are unsure of the correct answer, it is better to guess than to skip the question.
The probability will depend on how much you know and the extent of guessing.
The probability of getting both answers correct is one chance in nine (0.1111+). There are three possible answers for each question, so there is a 1/3 chance of getting the correct answer to one question. To get the correct answer for both questions, the chances are 1/3 x 1/3 or 1/9.
Please answer my question. I have been asking this question and not getting answers
It is 0.0033
Try rephrasing the question. By the way, I think this is an answer
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Let us say that for each question, there are n multiple choices. If this is true and false, then n=2. The chance of getting a right answer is 1/n and wrong answer (n-1)/n. I will define p as getting a wrong answer one time (p = (n-1)/n so the probability of 20 wrong answers is p20. Now for n = 4, p=0.75 and the chance of 20 wrong answers in a row is: (0.75)20= 0.0032 or 0.32%.
That depends on how many questions there are, how many choices are listed for each question, and whether any obviously-stupid answers are included among the choices. If any of those factors changes, then the probability changes. One thing we can guarantee, however, even without knowing any of these factors: If you have studied the subject and know the material, then your probability of getting correct answers increases dramatically.
The answer depends on the number of choices available for each question.
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question with options, you will lose of the credit for that question. Just like the similar multiple-choice penalty on most standardized tests, this rule is necessary to prevent random guessing. With five choices, your chance of getting the question wrong is 80% when guessing, and every wrong answer costs you 1/4 of a point. In this case, leave it blank with no penalty. Guessing becomes a much better gamble if you can eliminate even one obviously incorrect response. If you can narrow the choices down to three possibilities by eliminating obvious wrong answers