Counting from 000 to 999 would give a possible 1000 combinations.
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Possible solutions - using your rules are:- 11,13,17,31,33,37,71,73 &77
900 ,999 ,909
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
There are 2 possible digits for the first digit (3 or 4), leaving 3 possible digits for the second digit (5 and 6 and whichever was not chosen for the first), leaving 2 possible digits for the third. Thus there are 2 × 3 × 2 = 12 possible 3 digit numbers.
2 * 2 * 2 * 2 It's not possible to make 16 without using the same numbers twice or without using whole numbers.