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Q: What is -4 plus 4y2?

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4y2 + 25y + 6

4(y + 2)(y + 2)

(4y2 + 3)(4y2 - 6y + 3)(4y2 + 6y + 3)

4(y + 2)(y + 2)

In the equation x = 4y2 + 6 where x = 42, we need to substitute 42 for x and solve for y. x = 4y2 + 6 42 = 4y2 + 6 42 - 6 = 4y2 + 6 - 6 36 = 4y2 36 / 2 = 4y2 / 2 18 = 4y 18 / 4 = 4y / 4 9 / 2 = y 4 1/2 = y (or 4.5 = y)

8me+8you because 4y2 = 2(4y) = 8y

4y2+16y+16=0 Divide by 4 on both sides: y2+4y+4=0 Factorise: (y+2)(y+2)=0 Therefore y= -2

4y2+25y+6 = (4y+1)(y+6) when factored with the help of the quadratic equation formula

(2y-11)^2

(4y + 1)(y + 6)

(y - 5)(4y - 5)

4(4x^4 + y^2)

(2y + 3)(4y2 - 6y +9)

(4y - 1)(y + 2)

The expression in the question does not define an area.

If you're looking to factor this expression, then you need to find two values that add up -20, and which multiply to make 4. Unfortunately, no such terms exist, so this expression can not be factored.

4y2+37a-15=0

2(2)2 + 3(2)(- 4) - 4(- 4)2 8 - 24 - 64 = - 80 ======

10y^2 -12

4y2 + 16y + 16 = 4(y2 + 4y + 4) = 4(y2 + 2y + 2y + 2) = 4[y(y + 2) + 2(y + 2)] = 4(y + 2)2

hyperbola

15t(10y^3t^5 +5y^2 t)-2y(yt^2 +4y^2)

(2y + 3)(4y^2 - 6y + 9)

Do you mean -4y2+32y-64 = 0 otherwise it's not an equation because there's no equal sign If so then by using the quadratic equation formula the values of y both equal 4

No, it equals 4y2