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2 cos2(x) - sin(x) - 1
= 2 (1 - sin2(x)) - sin(x) - 1
= 2 - 2 sin2(x) - sin(x) - 1
= -2 sin2(x) - sin(x) +1
No, (sinx)^2 + (cosx)^2=1 is though
1/2(x-ln(sin(x)+cos(x)))
sin x/(1+cos x) + cos x / sin x Multiply by sin x (1+cos x) =[(sin^2 x + cos x(1+cos x) ] / sin x (1+cos x) = [(sin^2 x + cos x + cos^2 x) ] / sin x (1+cos x) sin^2 x + cos^2 x = 1 = (1+cos x) / sin x (1+cos x) = 1/sin x
The answer is 1. sin^2 x cos^2/sin^2 x 1/cos^2 cos^2 will be cancelled =1 sin^2 also will be cancelled=1 1/1 = 1
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