a(x5) + b(x5) + c(x5) + d(x5) + e(x5) = abcde(a+b+c+d+e) x5 = abcdeThis equation has at least 5 variables. To solve for all of them requires at least 4 more equations.
5+5x5=30 but (5+5)x5=50
Since x and y are variables, the sum of 5x and 5y could be literally any number.
1,565 = x5 1,5651/5 = (x5)1/5 1,5651/5 = x5/5 1,5651/5 = x 4.3541 = x
11x5=55 !
The additive inverse is x5 + 2x - 2.
Assuming that the question is find x in x5=1610; the answer is 4.378901
5x + 5y = 5(x+y)
For the equation: x5+7x3-30x=0 The highest exponent in the entire equation is 5 (from x5), so the equation is of degree 5.
512 x 5 = 2,560
is a quintic expression in x (NOT an equation).
5 times 5 equals 25.