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What is the exact value of tan 195?
The exact value of (\tan 195^\circ) can be found using the tangent addition formula. Since (195^\circ) is in the third quadrant, where tangent is positive, we can express it as (\tan(180^\circ + 15^\circ)). This gives us (\tan 195^\circ = \tan 15^\circ), which is (\frac{\sin 15^\circ}{\cos 15^\circ}). Using the known values, (\tan 15^\circ = 2 - \sqrt{3}). Therefore, (\tan 195^\circ = 2 - \sqrt{3}).
What is tan22.5?
The value of (\tan(22.5^\circ)) can be calculated using the half-angle formula for tangent: [ \tan\left(\frac{x}{2}\right) = \frac{1 - \cos(x)}{\sin(x)} ] For (x = 45^\circ), this simplifies to: [ \tan(22.5^\circ) = \sqrt{2} - 1 \approx 0.4142 ] Thus, (\tan(22.5^\circ)) is approximately 0.4142.
What is the value of tan 15 degree in fraction?
The value of ( \tan 15^\circ ) can be calculated using the tangent subtraction formula: [ \tan(15^\circ) = \tan(45^\circ - 30^\circ) = \frac{\tan 45^\circ - \tan 30^\circ}{1 + \tan 45^\circ \tan 30^\circ} ] Substituting the known values ( \tan 45^\circ = 1 ) and ( \tan 30^\circ = \frac{1}{\sqrt{3}} ), we find: [ \tan(15^\circ) = \frac{1 - \frac{1}{\sqrt{3}}}{1 + 1 \cdot \frac{1}{\sqrt{3}}} = \frac{\sqrt{3} - 1}{\sqrt{3} + 1} ] Thus, ( \tan 15^\circ = 2 - \sqrt{3} ) in its simplest fractional form.
Tan 9 plus tan 81 -tan 27-tan 63?
tan(9) + tan(81) - tan(27) - tan(63) = 4
What is the formula for finding end to center dimensions on a long radius butt weld elbow?
1/2 tan(dia)1.5
What is the formula of tan2x?
The formula for (\tan(2x)) is given by the double angle identity: [ \tan(2x) = \frac{2\tan(x)}{1 - \tan^2(x)} ] This formula allows you to express the tangent of double an angle in terms of the tangent of the original angle (x).
What is the half angle formula to find the exact value for tan 165?
tan u/2 = sin u/1+cos u
What is the formula of propeller pitch?
propeller pitch= 2 pi r tan a
What is the answer to y equals 2 tan 2x?
y = 2*tan(2x) is an equation in two variable. There can be no answer. While x can be made the subject of the formula, that is not an *answer*.
What is tan20tan32 plus tan32tan38 plus tan38tan20?
This may not be the most efficient method but ... Let the three angle be A, B and C. Then note that A + B + C = 20+32+38 = 90 so that C = 90-A+B. Therefore, sin(C) = sin[(90-(A+B) = cos(A+B) and cos(C) = cos[(90-(A+B) = sin(A+B). So that tan(C) = sin(C)/cos(C) = cos(A+B) / sin(A+B) = cot(A+B) Now, tan(A+B) = [tan(A)+tan(B)] / [1- tan(A)*tan(B)] so cot(A+B) = [1- tan(A)*tan(B)] / [tan(A)+tan(B)] The given expressin is tan(A)*tan(B) + tan(B)*tan(C) + tan(C)*tan(A) = tan(A)*tan(B) + [tan(B) + tan(A)]*cot(A+B) substituting for cot(A+B) gives = tan(A)*tan(B) + [tan(B) + tan(A)]*[1- tan(A)*tan(B)]/[tan(A)+tan(B)] cancelling [tan(B) + tan(A)] and [tan(A) + tan(B)], which are equal, in the second expression. = tan(A)*tan(B) + [1- tan(A)*tan(B)] = 1
What is the formula for pipe length between 45 degree elbows?
Tan 45/2*dia*1.5*25.4
What is the exact value of tan 195?
The exact value of (\tan 195^\circ) can be found using the tangent addition formula. Since (195^\circ) is in the third quadrant, where tangent is positive, we can express it as (\tan(180^\circ + 15^\circ)). This gives us (\tan 195^\circ = \tan 15^\circ), which is (\frac{\sin 15^\circ}{\cos 15^\circ}). Using the known values, (\tan 15^\circ = 2 - \sqrt{3}). Therefore, (\tan 195^\circ = 2 - \sqrt{3}).
How do you apply wedge formula?
Fixdi=Foxdo Fixb+Foxh MA=Fo/Fi
What is tan22.5?
The value of (\tan(22.5^\circ)) can be calculated using the half-angle formula for tangent: [ \tan\left(\frac{x}{2}\right) = \frac{1 - \cos(x)}{\sin(x)} ] For (x = 45^\circ), this simplifies to: [ \tan(22.5^\circ) = \sqrt{2} - 1 \approx 0.4142 ] Thus, (\tan(22.5^\circ)) is approximately 0.4142.
What is the value of tan 15 degree in fraction?
The value of ( \tan 15^\circ ) can be calculated using the tangent subtraction formula: [ \tan(15^\circ) = \tan(45^\circ - 30^\circ) = \frac{\tan 45^\circ - \tan 30^\circ}{1 + \tan 45^\circ \tan 30^\circ} ] Substituting the known values ( \tan 45^\circ = 1 ) and ( \tan 30^\circ = \frac{1}{\sqrt{3}} ), we find: [ \tan(15^\circ) = \frac{1 - \frac{1}{\sqrt{3}}}{1 + 1 \cdot \frac{1}{\sqrt{3}}} = \frac{\sqrt{3} - 1}{\sqrt{3} + 1} ] Thus, ( \tan 15^\circ = 2 - \sqrt{3} ) in its simplest fractional form.
What is the formula for finding the direction for a vector?
To find the direction of a vector, you can use the formula: θ = tan^(-1) (y/x), where θ is the angle of the vector with the positive x-axis, and (x, y) are the components of the vector along the x and y axes, respectively.
What is the Formula to calculate KVAR?
{| |- | capacitance of the capacitor is mentioned in KVAR. Formula : KVAR = KW*tan@ FOR tan@, First note the power factor & KW without connecting capacitor. The noted power factor is in cos@.Convert the cos@ value in tan@. for ex. If power factor is 0.6, KW = 200 cos@ = 0.6 cos-1 (0.6) = 53.1 tan (53.1) = 1.333 200*1.333 = 266.6 KVAR if you use 266 KVAR capacitor, Then the power factor improves to unity (1.000). |}
