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Use the definition of "average", as follows.Add all the numbers up. Call the result "sum". Then count how many numbers there are, and divide "sum" by that number.

In this particular case, the interval between any two consecutive numbers is the same (an arithmetic sequence); in this case, you can use the following shortcut: the average is simply the number in the middle. (And if there are an even number of numbers, take the average between the two numbers in the middle.)

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The average of the above numbers is 18

Q: What is the average of 3 8 13 18 23 28 33?

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It is: 5n+3 and so the next term is 28

The 'n'th term is [ 13 + 5n ].

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The sum is 93.

18 / 5 = 3 remainder 3 Answer: 18 Other possible correct answers are: 8 13 23 28 3

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8, 13, 18, 23, 28, etc.

23

The 'n'th term is [ 13 + 5n ].

The 'n'th term is [ 13 + 5n ].

The 'n'th term is [ 13 + 5n ].

It is: 5n+3 and so the next term is 28

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The sum is 93.

Halfway between 18 and 28 is (18 + 28) ÷ 2 = 23.

t{n} = (3n⁵ - 45n⁴ + 255n³ - 675n² + 1022n - 240)/40 This gives t{1..5} = {8, 13, 18, 23, 28} and continues t{6...} = {42, 92, 232, 552, 1187, ...} However, your teacher probably wants the much simpler: t{n} = 5n + 3 Which also gives t{1..5} = {8, 13, 18, 23, 28} but continues t{6...} = {33, 38, 43, 48, ...} There are infinitely many formulae that can be given to give the terms t{1..5} = {8, 13, 18, 23, 28}; they all differ in what terms follow. Which means that any formula for the nth term of t{1..5} = {8, 13, 18, 23, 28} is ONLY valid for n = 1, 2, ..., 5 as 5 terms have been given.

28

18