t{n} = (3n⁵ - 45n⁴ + 255n³ - 675n² + 1022n - 240)/40
This gives t{1..5} = {8, 13, 18, 23, 28}
and continues t{6...} = {42, 92, 232, 552, 1187, ...}
However, your teacher probably wants the much simpler:
t{n} = 5n + 3
Which also gives t{1..5} = {8, 13, 18, 23, 28}
but continues t{6...} = {33, 38, 43, 48, ...}
There are infinitely many formulae that can be given to give the terms t{1..5} = {8, 13, 18, 23, 28}; they all differ in what terms follow.
Which means that any formula for the nth term of t{1..5} = {8, 13, 18, 23, 28} is ONLY valid for n = 1, 2, ..., 5 as 5 terms have been given.
Un = 5n - 2
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
It is: 10n-7 and so the next term is 43
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
Un = 5n - 2
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
It is: 5n+3 and so the next term is 28
The 'n'th term is [ 13 + 5n ].
18,23,28,33,... #1 is 18 #2 is 23 A difference of '5' Hence we can write '5n + x = 18 Where 'n' equals '1' Hence 5(1) + x = 18 5 + x = 18 Hence x = 18 - 5 = 13 So nth term is 5n + 13 NB Verification; does it work for the 4th term 5(4)+ 13 = 20 + 13 = 33 Which is true from above list.
14+9n
It is: 10n-7 and so the next term is 43
58
A simple answer, based on a linear rule is U(n) = 5n - 23 for n = 1, 2, 3, ...
All you have to do is add 5 each time(x+5) It's 43
Assuming the pattern would continue: 25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15, 14, 13...