2.5
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y = 5/x^(2) =>
y = 5x^(-2)
dy/dx = 5(-2)x^(-3)
dy/dx = -10 x^(-3)
dy/dx = -10/x^(3) .
3x4 plus 5x3 plus x2 - 5 divided by x 2 =[(3x4) + (5x3) + (x2 - 5)]/x2 =(12 + 15 + x2 -5)/x2 =(27 - 5 + x2)/x2 =(22 + x2)/x2
20x -5
If you mean: f(x) = x4 - 3x3 + 5x2 / x2 then: f(x) = x4 - 3x3 + 5 ∴ f'(x) = 4x3 - 9x2 If you mean: f(x) = (x4 - 3x3 + 5x2) / x2 then: f(x) = x2 - 3x + 5 ∴ f'(x) = 2x - 3
-4 / x3
The derivative, with respect to x, is -x/sqrt(1-x2)