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What is the equation for 2 -7?

Updated: 12/15/2022
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AnaOrellanafb0336

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8y ago

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Cassandra Carroll

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3y ago
This answer is:
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Wiki User

8y ago

It is 2 - 7 = -5

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Q: What is the equation for 2 -7?
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What is the equation of 2x 1 equals 7?

im assuming your equation is 2x + 1 = 7 in this case you need to find what x equals 2x + 1 = 7 2x + 1 - 1 = 7-1 2x = 6 x = 3 put it back into the equation to check if your answer is correct 2(3) + 1 = 7 6 + 1 = 7 7 = 7 Correct! if your equation is 2x - 1 = 7 x = 4 check it 2(4) - 1 = 7 8 - 1 = 7 7 = 7 Correct! if your equation is 2x1 = 7 x = 7/2 check it 2(7/2)1 = 7 2(7/2) = 7 2 * 7 / 2 = 7 14/2 = 7 7 = 7 Correct! hope i got your equation right. if not you can message me on my message board to get more help.


What is the equation of 7 to the negative 2 power as a positive?

7-2 IS positive. You do not need an equation for it. And if it were not positive, no correct equation would show it to be positive.


What is the equation of the circle with a radius of 7 whose center is in the 1st quadrant and touches both the x and y axes?

Equation of the circle: (x-7)^2 +(y-7)^2 = 49


What is the equation of the points 72 and 00?

If you mean points (7, 2) and (0, 0) then the slope is 2/7 and equation is y = 2/7x


What is the equation of the circle with center 2 9 and radius 7?

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What is the algebraic equation for half a number plus 7?

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It seems that the equation you provided is not clear. "x - 2 5 and 7 equal 2 and 3" doesn't form a valid equation. If you can provide a clearer equation, I can help you solve it.


What is the equation of the circle with center (2 -9) and radius 7?

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What is the Cartesian equation of a circle whose centre is in the 1st quadrant with a radius of 7 and touches the x and y axes?

Centre of the circle is at (7, 7) and its Cartesian equation is (x-7)^2 + (y-7)^2 = 49


What is the equation of the line passing through the given points 1 and 5 and 2 and 7?

Points: (1, 5) and (2, 7) Slope: 2 Equation: y = 2x+3