im assuming your equation is 2x + 1 = 7 in this case you need to find what x equals 2x + 1 = 7 2x + 1 - 1 = 7-1 2x = 6 x = 3 put it back into the equation to check if your answer is correct 2(3) + 1 = 7 6 + 1 = 7 7 = 7 Correct! if your equation is 2x - 1 = 7 x = 4 check it 2(4) - 1 = 7 8 - 1 = 7 7 = 7 Correct! if your equation is 2x1 = 7 x = 7/2 check it 2(7/2)1 = 7 2(7/2) = 7 2 * 7 / 2 = 7 14/2 = 7 7 = 7 Correct! hope i got your equation right. if not you can message me on my message board to get more help.
Equation of the circle: (x-7)^2 +(y-7)^2 = 49
depends on the equation.
x - 2 5/7 = 2/3 x - 19/7 = 2/3 x = 2/3 - 19/7 = 14/21 - 57-21 = -43/7 = -6 and 1/7
x/7 = 2 Multiply both sides by '7' 7x/7 = 7 x 2 = 14 On LHS cancel down '7' Hence x = 14
im assuming your equation is 2x + 1 = 7 in this case you need to find what x equals 2x + 1 = 7 2x + 1 - 1 = 7-1 2x = 6 x = 3 put it back into the equation to check if your answer is correct 2(3) + 1 = 7 6 + 1 = 7 7 = 7 Correct! if your equation is 2x - 1 = 7 x = 4 check it 2(4) - 1 = 7 8 - 1 = 7 7 = 7 Correct! if your equation is 2x1 = 7 x = 7/2 check it 2(7/2)1 = 7 2(7/2) = 7 2 * 7 / 2 = 7 14/2 = 7 7 = 7 Correct! hope i got your equation right. if not you can message me on my message board to get more help.
7-2 IS positive. You do not need an equation for it. And if it were not positive, no correct equation would show it to be positive.
Equation of the circle: (x-7)^2 +(y-7)^2 = 49
If you mean points (7, 2) and (0, 0) then the slope is 2/7 and equation is y = 2/7x
depends on the equation.
x/2 + 7
xy +7
x - 2 5/7 = 2/3 x - 19/7 = 2/3 x = 2/3 - 19/7 = 14/21 - 57-21 = -43/7 = -6 and 1/7
x/7 = 2 Multiply both sides by '7' 7x/7 = 7 x 2 = 14 On LHS cancel down '7' Hence x = 14
Equation of circle: (x-2)^2 +(y+9)^2 = 49
Centre of the circle is at (7, 7) and its Cartesian equation is (x-7)^2 + (y-7)^2 = 49
Points: (1, 5) and (2, 7) Slope: 2 Equation: y = 2x+3