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As there is a repeated x-coordinate, x = f(y), giving:

As it is a parabola, x = ay² + by + c, so substituting the known points:

  1. (0, 0) → 0 = 0²x + 0b + c → 0 = c
  2. (20, 12) → 20 = 12²a + 12b + c → 20 = 144a + 12b + c
  3. (0, 40) → 0 = 40²a + 40b + c → 0 = 1600a + 40b + c

From equation 1, c = 0, so substituting in the second and third equations gives two new equations involving two unknowns:

  1. 20 = 144a + 12b
  2. 0 = 1600a + 40b
The second of these can be simplified to give:

0 = 40a + b

→ b = -40a

This can be substituted back into the first to give:

20 = 144a + 12 b

→ 20 = 144a + 12(-40a)

→ 20 = 144a - 480a

→ 20 = -336a

→ a = -5/84

→ b = -40a = -40(-5/84) = 50/21

→ x = -5/84 y² + 50/21 y

→ 84x = -5y² + 200y

→ 84x = 200y - 5y²

The parabola has equation 84x = 200y - 5y²

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A parabola which goes through (0, 0) and (0, 40) cannot be a function: no function can be one-to-many.

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Q: What is the equation of the function of the parabola that contains the points 0 0 20 12 0 40?
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