(a + x^2)(b + y^2)
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
(x + 3)(x + 3)
(x+1)(x+8)
(x + 3)(x + 2)
(a + x^2)(b + y^2)
No
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
x2y + axy + abx + a2b Factor by grouping. xy(x + a) + ab(x + a) (xy + ab)(x + a)
Oh, dude, you're hitting me with some math now? Alright, so you're looking at the quadratic expression x^2 + 5x + 4. To factor this, you want to find two numbers that multiply to 4 (the constant term) and add up to 5 (the coefficient of the x term). Those numbers are 1 and 4, so the factored form is (x + 1)(x + 4). That's it, easy peasy lemon squeezy!
(x + 2)(x + 1)
(x + 3)(x + 3)
(x+1)(x+8)
(x + 3)(x + 2)
4(x+y)^2
(x-5i)(x+5i)
it is (x-y)(x-y) :)