6*sqrt(2) = 8.4853 cm.
6*sqrt(2) = 8.4853 cm.
6*sqrt(2) = 8.4853 cm.
6*sqrt(2) = 8.4853 cm.
6*sqrt(2) = 8.4853 cm.
The length of one side of a square with a 16-centimeter diagonal is: 11.31 cm
You don't. One measures length, the other measures area.
Use Pythagoras' theorem: 62+32 = 45 and the square root of 45 is about 6.708203932 cm
The diagonal length of a square with a 900 square foot area is: 42.43 feet.
If the length of a side of the square is S units then the diagonal is S*sqrt(2) units in length.
The length of one side of a square with a 16-centimeter diagonal is: 11.31 cm
A square centimeter measures area, and a centimeter measures length, so they are not exactly comparable in size.
~7.1 cm
42 cm
You don't. One measures length, the other measures area.
A diagonal of a square measures: Side X sqrt(2).Approximately (8 cm) X (1.414) = 11.312 cm
Use Pythagoras' theorem: 62+32 = 45 and the square root of 45 is about 6.708203932 cm
Divide the length of the diagonal of a square by 1.4142 (which is the square root of 2) to find the length of a side. Similarly, to find the length of the diagonal of a square, multiply the length of a side by 1.4142.
As a square has right angles, the diagonal forms a right triangle with two of the sides of the square. Therefore use Pythagoras: diagonal² = side² + side² → diagonal² = 2side² → diagonal = side × √2 Therefore to find the length of the diagonal of a square, multiply the side length of a square by the square root of 2.
The diagonal length = 7.07 inches.
Using Pythagoras' theorem: 8 times the square root of 2 which is about 11,3137085 cm
Designate the length by L. From the Pythagorean theorem, the length of the diagonal of a square, which divides the square into two right triangles, each with sides L (and the diagonal as hypotenuse to each right triangle), is square root of 2L2 = 4 (from the problem statement). Squaring both sides separately yields 2L2 = 16 or L = square root of 8 = 2 (square root of 2).