Using Pythagoras; theorem it is 12 times square root of 2 which is about 17 cm rounded to the nearest integer
Designate the length by L. From the Pythagorean theorem, the length of the diagonal of a square, which divides the square into two right triangles, each with sides L (and the diagonal as hypotenuse to each right triangle), is square root of 2L2 = 4 (from the problem statement). Squaring both sides separately yields 2L2 = 16 or L = square root of 8 = 2 (square root of 2).
To find the diagonal of a square, we can use the formula for the diagonal of a square, which is d = sā2, where d is the diagonal length and s is the side length of the square. Given that the area of the square is 36, we can find the side length by taking the square root of the area, which is ā36 = 6. Substituting s = 6 into the formula, we get d = 6ā2. Therefore, the diagonal of the square with an area of 36 is 6ā2 units.
Each side = sqrt (182 / 2) = sqrt (162) = 12.72792 metres
The diagonal of a square whose area is 36 is the square root of 72, or about 8.49. Since the area of a square is side(squared), then the sides are each 6. Then since a(squared) + b(squared) = c(squared), for a triangle (the diagonal), you get the square root of 72.
The square's diagonal is 11.314 cm
The length of the diagonal of a square whose side lengths are 7 square root 2 (9.89949494) is: 14 units.
Using Pythagoras; theorem it is 12 times square root of 2 which is about 17 cm rounded to the nearest integer
Designate the length by L. From the Pythagorean theorem, the length of the diagonal of a square, which divides the square into two right triangles, each with sides L (and the diagonal as hypotenuse to each right triangle), is square root of 2L2 = 4 (from the problem statement). Squaring both sides separately yields 2L2 = 16 or L = square root of 8 = 2 (square root of 2).
4
Using Pythagoras's theorem, you will find that the diagonal is sqrt(2) = 1.4142 cm (approx),
a≈2.83cm The sides are the square root of 8 cm, approximately 2.8284 cm
There is no such thing as a square whose length and width are different.
A square with a side length of 6 inches has an area of 36 square inches.
The diagonal of a 46' x 46' square is 65.05 feet.
The diagonal of a square is usually found using Pythagoras's theorem, a2 + b2 = c2. Since this is a square, a = b; thus: c2 = 2s2, where s is the side length and c is the diagonal. s = square root(c2/2) = square root(625/2) = square root(312.5) = 17.8in The dimensions of a square whose diagonal is 25inches is 17.8in x 17.8in (rounded to the nearest tenth)
Using Pythagoras' theorem the length of the diagonal is 20 feet