3
The limit is 4.
2 divided by x-12-x divided by x-2 is -1/(6(x-2)).
The limit should be 0.
You can use the L'hopital's rule to calculate the limit of e5x -1 divided by sin x as x approaches 0.
1
Yes, it does.
d/dx((√12)/x)=-(√12)/x^2
4 + 3 x 12 divided by 2?
x/9 = 12 Therefore, x = 9 x 12 x = 108
18.75
0.5
x/4 = 12 so x = 4 x 12...