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What is the point of contact when the tangent line y equals x plus c touches the curve y equals 3 -x -5x squared?
Wiki User
∙ 6y ago
-2
Gardner Fisher
Wiki User
∙ 6y agoIf: y = x +c and y = 3 -x -5x^2
Then: x +c = 3 -x -5x^2
Transposing terms: 5x^2 +2x +(c -3) = 0
Using the discriminant formula: 2^2 -4*5*(c -3) = 0 => c = 16/5
Using the quadratic equation formula: 5x^2 -2x +1/5 = 0 => x = -1/5
By substitution: y = 3
Therefore the point of contact is made at: (-1/5, 3)
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What is the point of contact when the tangent line y equals x plus c touches the curve y equals 3x -x -5x squared?
-2
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What is the value of k when y equals 3x plus 1 and is a line tangent to the curve of x squared plus y squared equals k?
k = 0.1
How do you solve secant squared divided by tangent?
In trig, the secant squared divided by the tangent equals the hypotenuse squared divided by the product of the opposite and adjacent sides of the triangle.Details: secant = hypotenuse/adjacent (H/A) and tangent = opposite/adjacent (A/O);Then secant2/tangent = (H2/A2)/(O/A) = H2/A2 x A/O = H2/AO.
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