Assuming the dice are unbiased standard dice, then
To get a mean average of 6, every dice must show a six → probability = 1/(6^4) = 1/1296 ≈ 0.000772
To get a median average of 6, then only 3 of the dice need show a six. In this case there are:
all 4 dice show a 6 = 1 way
To select 3 dice to show 6 leaves 1 die which can show any number 1-5. There are 4 ways this single die can be left giving 5 × 4 possible ways = 20 ways
This gives a total of 1 + 20 = 21 ways of it happening and the probability is 21/1296 ≈ 0.0162
To get a mode average of 6 is slightly complicated: all 4 dice can show a 6, three dice can show a 6 ,or 2 dice can show a 6 AND the other 2 dice show different numbers. There are:
1 way all 4 show a 6 (as above)
20 ways exactly 3 show a 6 (as above)
2 show a six:
2 dice are selectable in 4 × 3 = 12 ways.
Of the other 2 dice one can show one of 5 numbers and the other one of the remaining 4 which is 5*4 = 20, making 12*20 = 240 ways
Thus there are a total of 240+20+1 = 261 ways of it happening and the probability is 261/1296 ≈ 0.2014
It is 1/6^4 = 1/1296 = 0.0007716 (approx).
Please note that you can only get an average of 6 if each and every die gives you a six.
What is the probability of 1, 6, 4, on 3 rolls of a die
The probability of rolling a 2 is 1 in 6. The probability of rolling an even number is 3 in 6. The probability of doing both, on two rolls, is 3 in 36, or 1 in 12.
Anywhere from 0 to 1; it depends on the shape and what numbers are written on the faces.
The probability of not rolling it ever is 0.For n rolls it is (5/6)n sofor 10 rolls it is 0.1615for 20 rolls it is 2.608*10-2for 100 rolls it is 1.207*10-8 and so on.
Total number of possible rolls with 2 dice = 36.Total number of rolls that are doubles = 6.Probability of rolling doubles= 6/36 = 1/6 = (16 and 2/3) percent .
The probability of getting an even number on at least one of the 3 rolls is 7/8.
The answer depends on how often you roll it! For one roll it is 1/6 but the probability increases to a near certainty as you increase the number of rolls.
What is the probability of 1, 6, 4, on 3 rolls of a die
about half a mill.
The probability that each roll will be a 1, is 1/6 (a sixth) because there is one outcome of interest (getting a 1) and 6 possible outcomes (6 numbers on the die).Probability rules mean that if you want the probability of getting outcome A and getting outcome B then the total probability is P(A) x P(B) where P(A) means the probability of getting outcome A).In short if you want P(A and B) then this is P(A) x P(B)Applied to this example if you want the probability of getting a 1 on each throw of the die (i.e. on all 3 throws) then the probability is given by:P(1 on all three rolls) = P(1 on first roll) x P(1 on second role) x P(1 on third role)P(1 on all three rolls) = 1/6 x 1/6 x 1/6P(1 on all three rolls) = 1 / 216
The probability of rolling a 2 is 1 in 6. The probability of rolling an even number is 3 in 6. The probability of doing both, on two rolls, is 3 in 36, or 1 in 12.
Probability is the likelihood that something will occur. If you subtract it from 1, we get the likelihood (or probability) that it will not occur. If a coin is tossed and rolls heads 6 times, the (empirical) probability of obtaining a head is 6/10 or .6. 1-.6 =.4 is the empirical probability (or likelihood) of not getting a head.
Anywhere from 0 to 1; it depends on the shape and what numbers are written on the faces.
The probability of not rolling it ever is 0.For n rolls it is (5/6)n sofor 10 rolls it is 0.1615for 20 rolls it is 2.608*10-2for 100 rolls it is 1.207*10-8 and so on.
Total number of possible rolls with 2 dice = 36.Total number of rolls that are doubles = 6.Probability of rolling doubles= 6/36 = 1/6 = (16 and 2/3) percent .
With a fair die, it is 1/216 in three rolls, but the probability increases to 1 (a certainty) as the number of rolls is increased.
1/4? ...