The first 10 positive whole numbers are: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10.
The even numbers among those are 2, 4, 6, 8, 10.
So there are 5 ways of choosing an even number from among the first 10 positive whole numbers.
Of the first 10 positive whole numbers, 2, 4, 6, 8, and 10 are even. So 5 in 10 or 50%
If I understand the question correctly, it is 0.5
The probability is 0.5
If you chose the number out of an equal numberof odd and even numbers then it would be 50% chance. Like if you chose an odd number out of the numbers from 1 to 100
Probability values are never negative and are always between 0-1 according to the definition Probability of A= Number of outcomes classified as A/Total number of possible outcomes
The value of a probability is a number between 0 and 1 So it's either positive and less or equal to one or null
Although there are infinitely many primes, they become rarer and rarer so that as the number of numbers increases, the probability that picking one of them at random is a prime number tends to zero*. In the first 10 numbers there are 4 primes, so the probability of picking one is 4/10 = 2/5 = 0.4 In the first 100 numbers there are 26 primes, so the probability of picking one is 25/100 = 1/4 = 0.25 In the first 1,000 numbers there are 169 primes, so the probability of picking one is 168/1000 = 0.168 In the first 10,000 numbers there are 1,229 primes, so the probability of picking one is 0.1229 In the first 100,000 numbers there are 9592 primes, so the probability of picking one is 0.09592 In the first 1,000,000 numbers there are 78,498 primes, so the probability of picking one is 0.078498 In the first 10,000,000 numbers there are 664,579 primes, so the probability of picking one is 0.0664579 * Given any small value ε less than 1 and greater than 0, it is possible to find a number n such that the probability of picking a prime at random from the numbers 1-n is less than the given small value ε.
The probability is 8/20.
There are 12 composite (and 8 primes) in the first twenty whole numbers. So the probability of randomly choosing a non-prime is 12/20 or 60%.
If you have an equal amount of odd and even numbers in a determined sample space, the probability of choosing and odd number is 1/2 (.5).
The prime numbers from one to nine are 2, 3, 5, and 7. There are nine numbers from one to nine. The probability is 4 (the number of prime numbers) over 9 (the total number of numbers). Therefore, the probability of choosing a prime number is 4/9 or about 44 percent.
If you chose the number out of an equal numberof odd and even numbers then it would be 50% chance. Like if you chose an odd number out of the numbers from 1 to 100
Six.
1 / total number of people
The probability is(the total number of numbers on the spinner minus 5)/(the total number of numbers on the spinner)Another way to express the same probability is1 - 5/(the total number of numbers on the spinner)
In the sample space [1,20], there are 8 prime numbers, [2,3,5,7,11,13,17,19]. The probability, then, of randomly choosing a prime number in the sample space [1,20] is (8 in 20), or (2 in 5), or 0.4. The probability of choosing two of them is (8 in 20) times (7 in 19) which is (56 in 1064) or (7 in 133) or about 0.05263.
Positive numbers always result in positive numbers when added, divided, or multiplied by another positive number.
Probability values are never negative and are always between 0-1 according to the definition Probability of A= Number of outcomes classified as A/Total number of possible outcomes
The probability is 1/b.
The probability is 0.