no
No.
(-2,-1)
2x2 + 3x - 20 = (x + 4)(2x - 5).
There is one solution for x and one solution for y. The solution is: x = -1 ; y = 2
no
What is the solution set of 2x2 + x = 15
No.
(-2,-1)
The solution is: x = 1 and y = -1
y=2x2+5. Plug in 0 for x, and you get y=2(0)^2 +5 =0+5=5. 5 is the minimum value for y.
2x2 + 3x - 20 = (x + 4)(2x - 5).
There is one solution for x and one solution for y. The solution is: x = -1 ; y = 2
Assuming the missing symbol there is an equals sign, then we have: y - 2x2 - 4x = 4 We can find it's vertex very easily by solving for y, and finding where it's derivative equals zero: y = 2x2 + 4x + 4 y' = 4x + 4 0 = 4x + 4 x = -1 So the vertex occurs Where x = -1. Now we can plug that back into the original equation to find y: y = 2x2 + 4x + 4 y = 2 - 4 + 4 y = 2 So the vertex is at the point (-1, 2)
In the equations Y=X-1 and Y=-X+1, the solution is (1,0)
x = 2.1374586088176875 x = -1.6374586088176875
y = 1