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In y = 2x - 6, this is a function, and the value of y varies linearly with x.
So, the number of values here is infinite, since there are an infinite number of values that can be given for x. More detail is needed.
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y=aX2+bX+c ---> y=X2-6X+5vertex formula is -b/2a( b=-6,a=1)vertex=-(-6)/2*1=6/2=3 y=32-6(3)+5---->y=-4so vertex is (3,4)
Use the slope formula (y2-y1)/(x2-x1) and yes x2 is the x-value of your second x coordinate. Meanwhile y2 is the second y coordinate.
It is 9, and the value of y is totally irrelevant.
that's x2 - y2 = (x-y)(x+y)
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y=aX2+bX+c ---> y=X2-6X+5vertex formula is -b/2a( b=-6,a=1)vertex=-(-6)/2*1=6/2=3 y=32-6(3)+5---->y=-4so vertex is (3,4)
6
Use the slope formula (y2-y1)/(x2-x1) and yes x2 is the x-value of your second x coordinate. Meanwhile y2 is the second y coordinate.
It is 9, and the value of y is totally irrelevant.
If: y = x2-7x+8 and y = -x2+9x-6 Then: x2-7x+8 = -x2+9x-6 So: 2x2-16x+14 = 0 => x2-8x+7 = 0 Therefore: x = 1 and x = 7 By substitution: x =1, y = 2 and x = 7, y = 8 Points of intersection: (1, 2) and (7, 8)
that's x2 - y2 = (x-y)(x+y)
if: y = x2 y = x + 6 then x2 = x + 6 => x2 - x - 6 =0 => (x - 3)(x + 2) = 0 => x = 3 or -2 => y = 9 or 4 respectively, ie the points (3, 9) and (-2, 4).
(Y2-Y1)/(X2-X1) Where Y2= second Y value (6) Y1= first Y value (5) same for X values (6-5)/(8-2)=1/6
(x + y)2 = x2 + 2xy + y2
change in Y divided by change in X. X is your field value(kilometers, miles, feet, etc) and Y is the units of your isolines(degrees, feet, meters, etc) Y2-Y1 / X2-X1 = Y2-Y1 DIVIDED BY X2-X1
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