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y=aX2+bX+c ---> y=X2-6X+5vertex formula is -b/2a( b=-6,a=1)vertex=-(-6)/2*1=6/2=3 y=32-6(3)+5---->y=-4so vertex is (3,4)
Use the slope formula (y2-y1)/(x2-x1) and yes x2 is the x-value of your second x coordinate. Meanwhile y2 is the second y coordinate.
It is 9, and the value of y is totally irrelevant.
if: y = x2 y = x + 6 then x2 = x + 6 => x2 - x - 6 =0 => (x - 3)(x + 2) = 0 => x = 3 or -2 => y = 9 or 4 respectively, ie the points (3, 9) and (-2, 4).
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y=aX2+bX+c ---> y=X2-6X+5vertex formula is -b/2a( b=-6,a=1)vertex=-(-6)/2*1=6/2=3 y=32-6(3)+5---->y=-4so vertex is (3,4)
Use the slope formula (y2-y1)/(x2-x1) and yes x2 is the x-value of your second x coordinate. Meanwhile y2 is the second y coordinate.
It is 9, and the value of y is totally irrelevant.
If: y = x2-7x+8 and y = -x2+9x-6 Then: x2-7x+8 = -x2+9x-6 So: 2x2-16x+14 = 0 => x2-8x+7 = 0 Therefore: x = 1 and x = 7 By substitution: x =1, y = 2 and x = 7, y = 8 Points of intersection: (1, 2) and (7, 8)
if: y = x2 y = x + 6 then x2 = x + 6 => x2 - x - 6 =0 => (x - 3)(x + 2) = 0 => x = 3 or -2 => y = 9 or 4 respectively, ie the points (3, 9) and (-2, 4).
(Y2-Y1)/(X2-X1) Where Y2= second Y value (6) Y1= first Y value (5) same for X values (6-5)/(8-2)=1/6
that's x2 - y2 = (x-y)(x+y)
(x + y)2 = x2 + 2xy + y2
It actually is f(x) = y. F is a function, based on x, that gives you a result for y. An example might be f(x) = x2. This means that for every value of x, y has a value of x2.
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