Ohms law will tell you watts equals volts times amps: 115 x 5 = 575
Multiply volts times amps to get watts: 115 * 5 = 575 W.
1 watt = 1 amp * 1 volt So.... In a house: 5 amps * 115 volts = 575 watts In a car: 5 amps * 12 volts = 60 watts
The formula you are looking for is Watts = Amps x Volts. Amps = Watts/Volts. This comes to 4 amps load. Minimum size fuse would be 5 amps.
Watts = Volts X Amps. Amps=Watt / Volts. So, with a 240V mains, a 60W bulb draws 0.25amps. On a 12 system (car/auto) a 60W bulb draws 5 amps. On a 110V mains, a 60W bulb draws .55 Amps.
5-115 = -110
1 × 115 = 115 5 × 23 = 115
1 watt = 1 amp * 1 volt So.... In a house: 5 amps * 115 volts = 575 watts In a car: 5 amps * 12 volts = 60 watts
A transformer does not use, it transforms voltage from one value to another. The output amperage is governed by the connected load. If the load wattage is higher than the wattage rating of the transformer then either the primary or secondary fuse will blow or the transformer will burn up if the fusing is of the wrong sizing. The maximum primary amperage can be found by using the following equation, Amps = Watts/Volts, A = W/E = 600/120 = 5 amps. The same equation is used for the calculating the maximum secondary amperage, A = W/E = 600/12 = 50 amps.
The switch will use no wattage whatsoever. The load on that switch is what uses power. If you know the load is 5 amps then 5 amps at 120 volts is 600 watts.
you would need to know the wattage of each lamp. multiply the lamp wattage x 5 = total watts divide the total wattage / 230 volts (or the voltage you will connect to)= amps example: 250 watts x 5= 1250 watts 1250 watts / 230 volts = 5.43 amps
You have your own answer. It is 1.5 amps.
There are no "watts" in 2.5 volts. Wattage is the result when you multiply volts times amps. You cannot answer the question with only one quantity (in this case 2.5 volts). If you have 1 amp and 2.5 volts, they you would have 2.5 watts. If you had 2 amps and 2.5 volts, they you would have 5 watts. The formula is Volts X Amps = Watts.
The 5 amp fuse has many wattages that it can protect. It depends on the voltage of the circuit that the fuse is protecting. Use the following formula, Watts = Volts x Amps. For example 120 volts x 5 amps = 600 watts, 240 volts x 5 amps = 1200 watts, 480 volts x 5 amps = 2400 watts and 600 volts x 5 amps = 3000 watts.
Two thoughts here, one the fixture should be rated at the maximum wattage allowed for the socket the bulb screws into. A label should state "maximum wattage allowed". To do a calculation Watts = Amps x Volts. Amps = Watts/Volts. 5 x 60 watts = 300 watts. 300/120 = 2.5 amps. The electrical code only rates down to #14 wire which is rated at 15 amps. From here you have to make the decision.
a 1.5 kVa source of electrical power has the capacity to supply 100 volts at 15 amps, 300 volts at 5 amps, or 1000 volts at 1.5 amps.
It depends on how many Amps (current) are applied to the voltage. Watt = Volts x Amps. e.g. 12 volts @ 5 amps = 60 watts
It depends on how many Amps (current) are applied to the voltage. Watt = Volts x Amps. e.g. 12 volts @ 5 amps = 60 watts
Formula: watts = amps times volts. The asumed voltage is 12 volts. So: watts = 5 amps times 12 volts = 60 watts. Cheers ebs