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What is the y intercept of the line passing through eight negative twelve with a slope of negative three-fourths?
Use the formula y=mx+c (Eqn 1)
m=-3/4
The line passes through (8, -12) so insert these values into Eqn 1
==> -12 = -3/4*8+c (I use * to mean multiply)
==> c = -12 +3/4*8 = -12 + 6 = -6
So the eqn of the line is y = -3/4x -6
The y intercept is found when x=0.
==> y = -3/4*0 - 6 = -6
So the y intercept is the point (0, -6)
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