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There is no operator between 3x and 84.
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What are three consecutive numbers that add up to 255?
84, 85, 86 x+x+1 + x+2 = 255 3x = 255 -1-2 =252 x = 252/3 = 84 therefore x + (x+1) + (x+2) = 84+ 85 + 86
Juan scored 5 points higher on his midterm and 13 points higher on his final than he did on his first exam If his mean average score was 90 what was his score on the first exam?
---- ASSUMPTIONS: First Exam = X Midterm Exam = X + 5 Final Exam = X + 13 Mean Average Score for the 3 exams above = 90 ---- SOLUTION: 90 = [X + (X + 5) + (X + 13)] / 3 90 * 3 = [X + (X + 5) + (X + 13)] 270 = 3X + 18 270 - 18 = 3X 252 = 3X 252 / 3 = X 84 = X Conclusion: Juan scored 84 points on his first exam. (See below for proof) ---- PROOF: First Exam = X = 84 Midterm Exam = X + 5 = 89 Final Exam = X + 13 = 97 Mean Average of 90 points --> [84 + 89 + 97] / 3 = 270 / 3 = 90
How do you factor 3x Squared plus x?
3x2 + x = x*(3x + 1)
What is the answer 3x divided 5-x divided 3 equals 4?
3x/(5-x)/3=4 3x/(5-x)=4X3 3x=12(5-x) 3x=60-12x 3x+12x=60 x=4
How do you do (x squared -2) (x squared 3x 5)?
(x^2-2) (x^2+3x+5)= x^2(x^2+3x+5) -2(x^2+3x+5)= x^4 +3x^3 +5x^2 -2x^2 -6x -10= x^4 +3x^3 +3x^2 -6x -10
What is x if 3x equals 84?
20
What is 3x-84?
3x-84 = -81
Solve for x in the following 3 over14 equals 84?
In order to solve for x, there must be an x in the equation.If you meant to say 3x/14=84, then 3x=14(84), so x=392 If you meant to say 3/14x=84, then 84x=3/14, so x=0.00255102041 If you meant to say 3/14=84x, then the above line is the answer.
What are three consecutive numbers that add up to 255?
84, 85, 86 x+x+1 + x+2 = 255 3x = 255 -1-2 =252 x = 252/3 = 84 therefore x + (x+1) + (x+2) = 84+ 85 + 86
What is 7x Minus 3x minus 4?
84
How do you distribute 3x(x-4)?
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
What is -3x - x?
- 3x - Xsame as- 3x + (- X)= - 4X=====
3x plus 4x equals 84 7x equals 84?
3x + 4x = 847x = 84divide both sides by 7x = 12
The sum of two numbers is 84 one number is three times the other what are the two numbers'?
a+b=84 a=3b 3b=84-b 4b=84 b=21 a=3*21 a=63 The two numbers are 21 and 63lets call the one number X and the other Y so y equals 3X so 3X+X equals 84 so 4X equals 84 we divide by 4 so x equals 21 so y equals 21*3 equals 63 so the two numbers are 63 and 21
Juan scored 5 points higher on his midterm and 13 points higher on his final than he did on his first exam If his mean average score was 90 what was his score on the first exam?
---- ASSUMPTIONS: First Exam = X Midterm Exam = X + 5 Final Exam = X + 13 Mean Average Score for the 3 exams above = 90 ---- SOLUTION: 90 = [X + (X + 5) + (X + 13)] / 3 90 * 3 = [X + (X + 5) + (X + 13)] 270 = 3X + 18 270 - 18 = 3X 252 = 3X 252 / 3 = X 84 = X Conclusion: Juan scored 84 points on his first exam. (See below for proof) ---- PROOF: First Exam = X = 84 Midterm Exam = X + 5 = 89 Final Exam = X + 13 = 97 Mean Average of 90 points --> [84 + 89 + 97] / 3 = 270 / 3 = 90
What is 3x squared minus 6x divided by 3x?
(3x2 - 6x)/3x = 3x(x-2)/3x = x-2, for x<>0
How do you do (3x 4)2?
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
