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What percentage of scores in a normal distribution fall between a z score of 36 and a z score of -25?
Wiki User
∙ 10y ago
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Savanna Parisian
Wiki User
∙ 10y agoVery close to 1.
1 - Prob (-6 < z < 6) = 1.97*10-9 approx or less than 2 in a billion.
So, Prob(-6 < z < z) > 999,999,998/1,000,000,000
By the time the range is extended to -25 and 36, the difference between the probability and the value 1 will be incredibly small.
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Assuming that you are refering to the standard normal distribution and the z-scores, the answer is 99.73%. If the assumption is incorrect, please resubmit the questionwith more information.
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How do you to get the probability in normal distribution?
You calculate the z-scores and then use published tables.
