Oh, dude, math time! So, when you divide 29 by 3, you get 9 with a remainder of 2. So, technically, there are 9 whole 3s in 29, but you're left with a little 2 hanging out at the end. Math can be a real party pooper sometimes, huh?
To find out how many 3s go into 140, divide 140 by 3. This gives you approximately 46.67. Since we're looking for whole 3s, you can fit 46 complete 3s into 140.
To find out how many 3s are in 120, you can divide 120 by 3. Performing the division, 120 ÷ 3 equals 40. Therefore, there are 40 threes in 120.
To find how many 3s go into 165, you divide 165 by 3. This calculation gives you 165 ÷ 3 = 55. Therefore, there are 55 threes in 165.
103
You can make 1 using three 3s by performing the following calculation: (3 + 3) / 3. Here, you add two 3s to get 6, and then divide by the third 3 to achieve the result of 1.
There are 29 3s because there also a 3 in the how many 3s are in 83333333333333333333333333333
To find out how many 3s go into 140, divide 140 by 3. This gives you approximately 46.67. Since we're looking for whole 3s, you can fit 46 complete 3s into 140.
To find out how many 3s are in 120, you can divide 120 by 3. Performing the division, 120 ÷ 3 equals 40. Therefore, there are 40 threes in 120.
To find how many 3s go into 165, you divide 165 by 3. This calculation gives you 165 ÷ 3 = 55. Therefore, there are 55 threes in 165.
Well, darling, there are two 3s in 78. Simple math, really. But hey, if you need help with anything else, I'm here to sprinkle some sass on it.
3x7+4x2
3 x 30 = 90 3 x 29 = 87
103
28 3s
The easiest way is to "flip" the inequality symbol end divide by the negative number:Example:6 < 3 - 3s6 - 3 < 3 - 3s -33 < -3s Method a) Divide by negative coefficient and flip the inequality symbol3/-3 > -3s/-3-1 > s or s< -13 < -3s Method b) Full algorithm, eliminate -3s by adding 3s on both sides3 +3s < -3s + 3s3 + 3s < 03 - 3 + 3s < 0 -33s < -33s/3 < -3/3s < -1 Looks familiar? So basically if you perform the full algorithm (method b) you can understand why we flip the inequality symbol when we have to eliminate a negative coefficient but it is faster just to flip the symbol (method a)
You can make 1 using three 3s by performing the following calculation: (3 + 3) / 3. Here, you add two 3s to get 6, and then divide by the third 3 to achieve the result of 1.
To determine how many times 3 fits into 24, you can divide 24 by 3. The calculation shows that 24 ÷ 3 = 8. Therefore, there are 8 threes in 24.