Assuming it's a plus sign, that factors to (2x + 1)(x + 4)
3(2x - 3)(x + 3)
If you mean: 2x^2 +9x +7 then it is (2x+7)(x+1) when factored
2x2 - 9x + 10 = 2x2 - 4x - 5x + 10 = 2x(x - 2) - 5(x - 2) = (x - 2)(2x - 5)
9x2 - 18x + 99(x2 - 2x + 1)==========
2x2+9x+9 = (2x+3)(x+3) when factored
(2x+3)(x+3)
3(2x - 3)(x + 3)
If you mean: 2x^2 +9x +7 then it is (2x+7)(x+1) when factored
2x2 - 9x + 10 = 2x2 - 4x - 5x + 10 = 2x(x - 2) - 5(x - 2) = (x - 2)(2x - 5)
9x2 - 18x + 99(x2 - 2x + 1)==========
3x^(2) +9x - 2x -6 Collect 'like terms'. Hence 3x^(2) + 7x - 6 Next write down all the factors of '3' and '6' Hence 3 ; 1' & 3' 6 ; 1,6 ; 2,3. From these pairs of number we select a pair from each coefficient, that add/multiply to '7' . Hence (3' x 3 ) & (1' x 2) ; NB 'dashes' (') to indicate source of numbers. Write up brackets (3x 2)(x 3) -2)(x + 3) Next we notice that the '6' is negative, so the two signs are different (+/-) The '7x' is positive , so the larger number takes the positive sign . Hence (3x - 2)(x + 3)
(2x+3)(x+3)
2x2+9x+9 = (2x+3)(x+3) when factored
2x2-9x+4 = (2x-1)(x-4) when factored
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
(6x^3-9x^2) / (2x-3) = 3x^2((2x-3) / (2x-3) = 3 x ^2 (3 x squared)
10 + 9x