Don't know
-2a^2
(a + x^2)(b + y^2)
b2 + ab - 2 - 2b2 + 2ab = -b2 + ab - 2 which cannot be simplified further.
ab=1a+1b a is equal to either 0 or two, and b is equal to a
That factors to (a + 1)(a + b) a = -1, -b b = -a
-2a^2
(a + x^2)(b + y^2)
b2 + ab - 2 - 2b2 + 2ab = -b2 + ab - 2 which cannot be simplified further.
ab=1a+1b a is equal to either 0 or two, and b is equal to a
x2y + axy + abx + a2b Factor by grouping. xy(x + a) + ab(x + a) (xy + ab)(x + a)
-132
That factors to (a + 1)(a + b) a = -1, -b b = -a
This expression can be factored. ab + 3a + b2 + 3b = a(b + 3) + b(b + 3) = (a + b)(b + 3)
4
If, as is normal, ab represents a times b, etc then ab + ab + cc = 2ab + c2 which is generally not the same as abc.
If you do not assume that "plus" is commutative, all that can be said that it is equal to A plus B.
In a right angled triangle its hypotenuse when squared is equal to the sum of its squared sides which is Pythagoras' theorem for a right angle triangle.