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How do you simplify x2-9 over x2-6x plus 9?
First you distribute: x2-9 = (x-3)(x+3) and that is you numerator. Distribute x2-6x+9. Find two #'s that mult. to make 9 and add to make 6. 3x3=9 and 3+3=6. now you replace the 6x with -3x and -3x so rewrite the problem as x2-3x-3x+9 then you distribute x(x-3)-3(x-3) so x2-6x+9 becomes (x-3)(x-3) and that is your denominator. Tharefore: (x-3)(x+3) over (x-3)(x-3) then cross out like terms and your answer is (x+3) over (x-3)
What is x2 plus 3x plus x plus 3?
X2+3x+x+3=x(x+1)+3(x+1)=(x+3)(x+1)
X2 plus 10x plus 21 by x plus 3?
(x2+10x+21)/(x+3) = (x+7)
What is x2 plus 2x plus 15 divided by x-3?
(x2 + 2x + 15)/(x - 3) = x + 5 + 30/(x - 3) where x ≠3
X2 plus 4x - 9 equals 5x plus 3?
x2 + 4x - 9 = 5x + 3 ∴ x2 - x - 12 = 0 ∴ (x + 3)(x - 4) = 0 ∴ x ∈ {-3, 4}
How do you simplify x2-9 over x2-6x plus 9?
First you distribute: x2-9 = (x-3)(x+3) and that is you numerator. Distribute x2-6x+9. Find two #'s that mult. to make 9 and add to make 6. 3x3=9 and 3+3=6. now you replace the 6x with -3x and -3x so rewrite the problem as x2-3x-3x+9 then you distribute x(x-3)-3(x-3) so x2-6x+9 becomes (x-3)(x-3) and that is your denominator. Tharefore: (x-3)(x+3) over (x-3)(x-3) then cross out like terms and your answer is (x+3) over (x-3)
What is x2 plus 3x plus x plus 3?
X2+3x+x+3=x(x+1)+3(x+1)=(x+3)(x+1)
X2 plus 10x plus 21 by x plus 3?
(x2+10x+21)/(x+3) = (x+7)
What is x2 plus 4x plus 3 factorised?
x2 + 4x + 3 = (x + 1)(x + 3)
How do you factor x3 plus x2-3x-3?
x3 + x2 - 3x - 3 x(x2 + x - 3) - 3
What is x2 plus 2x plus 15 divided by x-3?
(x2 + 2x + 15)/(x - 3) = x + 5 + 30/(x - 3) where x ≠3
X2 plus 4x - 9 equals 5x plus 3?
x2 + 4x - 9 = 5x + 3 ∴ x2 - x - 12 = 0 ∴ (x + 3)(x - 4) = 0 ∴ x ∈ {-3, 4}
What are the roots of x2 plus 6x plus 12 equals 0?
x2 + 6x + 12 = 0 x2 + 6x + 9 = -3 (x + 3)2 = -3 x + 3 = ± √-3 x = -3 ± i√3
What is x2 plus 6x plus 9 equals x plus 3?
x2+6x+9 = x+3 x2+6x-x+9-3 = 0 x2+5x+6 = 0 Solve by factoring or with the help of the quadratic equation formula: (x+3)(x+2) = 0 Therefore: x = -3 or x = -2
What is X times x plus three plus three times x plus three?
x(x + 3) + 3(x + 3) = x2 + 3x + 3x + 9 = x2 + 6x + 9 = (x + 3)(x + 3) = (x + 3)2
Solve x2 plus 4x plus 3 equals 0?
x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}
Factor x2 plus 6x plus 9?
(x + 3)(x + 3)
