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What is 16 equals the fraction of y 3?
do you mean 16 = y / 3 ?? if so, y = 48.
How is the square root of 16 related to the cube root of 16?
Suppose sqrt(16) = x and cuberoot(16) = y, then then x^2 = 16 = y^3 so that x^(2/3) = y x = y^(3/2).
Y equals 1 plus 3x and y equals 16-2x What is X and Y?
y = 1 + 3x y = 16 - 2x Because y = y, that means... 1 + 3x = 16 - 2x Solve for x... x = 3 Plug it back in to one of the original equations... Y = 1 + 3(3) = 10 So... x = 3 y = 10
What does 8y over y plus 2 plus 16 over y plus 2 equal?
8y/y + 2 + 16/y + 2 = 8 + 2 + 16/y +2 = 12 + 16/y = 4(3 + 4/y) or 4/y*(3y + 4)
X2 plus 4x plus y2-6y equals 3?
x2 + 4x + y2 - 6y = 3 You need to be more clear about your question: Are you trying to find the properties of the curve it defines? x2 + 4x + y2 - 6y = 3 ∴ x2 + 4x + 4 + y2 - 6y + 9 = 16 ∴ (x + 2)2 + (y - 3)2 = 42 ∴ This describes a circle with a radius of 4, and a center point of (-2, 3) Did you want to solve for y? (x + 2)2 + (y - 3)2 = 42 ∴ (y - 3)2 = 16 - (x + 2)2 ∴ y - 3 = ± [16 - (x + 2)2]1/2 ∴ y = 3 ± [16 - (x + 2)2]1/2 Did you want to solve for x? (x + 2)2 + (y - 3)2 = 42 ∴ (x + 2)2 = 16 - (y - 3)2 ∴ x + 2 = ± [16 - (y - 3)2]1/2 ∴ x = -2 ± [16 - (y - 3)2]1/2
What is 16 equals the fraction of y 3?
do you mean 16 = y / 3 ?? if so, y = 48.
How is the square root of 16 related to the cube root of 16?
Suppose sqrt(16) = x and cuberoot(16) = y, then then x^2 = 16 = y^3 so that x^(2/3) = y x = y^(3/2).
What is the slope of 3x plus y equals 16?
If: 3x+y = 16 Then: y = -3x+16 whereas -3 is the slope and 16 is the y intercept
Y equals 1 plus 3x and y equals 16-2x What is X and Y?
y = 1 + 3x y = 16 - 2x Because y = y, that means... 1 + 3x = 16 - 2x Solve for x... x = 3 Plug it back in to one of the original equations... Y = 1 + 3(3) = 10 So... x = 3 y = 10
What does 8y over y plus 2 plus 16 over y plus 2 equal?
8y/y + 2 + 16/y + 2 = 8 + 2 + 16/y +2 = 12 + 16/y = 4(3 + 4/y) or 4/y*(3y + 4)
What is the slope of 3x plus 5y equals 16?
3x + 5y = 16 5y = -3x + 16 y = -3/5 x + 16/5 By the slope-intercept form: y = mx + b where m = slope b = y-intercept Therefore, the slope is -3/5.
What is the equation of the line in point-slope form that passes through the points 9 1 and 4 16?
Points: (9, 1) and (4, 16) Slope: (1-16)/(9-4) = -3 Equation: y-1 = -3(x-9) => y = -3x+28 Equation: y-16 = -3(x-4) => y = -3x+28
X2 plus 4x plus y2-6y equals 3?
x2 + 4x + y2 - 6y = 3 You need to be more clear about your question: Are you trying to find the properties of the curve it defines? x2 + 4x + y2 - 6y = 3 ∴ x2 + 4x + 4 + y2 - 6y + 9 = 16 ∴ (x + 2)2 + (y - 3)2 = 42 ∴ This describes a circle with a radius of 4, and a center point of (-2, 3) Did you want to solve for y? (x + 2)2 + (y - 3)2 = 42 ∴ (y - 3)2 = 16 - (x + 2)2 ∴ y - 3 = ± [16 - (x + 2)2]1/2 ∴ y = 3 ± [16 - (x + 2)2]1/2 Did you want to solve for x? (x + 2)2 + (y - 3)2 = 42 ∴ (x + 2)2 = 16 - (y - 3)2 ∴ x + 2 = ± [16 - (y - 3)2]1/2 ∴ x = -2 ± [16 - (y - 3)2]1/2
How many three- fourths are in 12?
How many [x] are in [y], where x and y are numbers, can be found by dividing y by x. In this case y=12, x=3/4. y/x=12/(3/4)=16. There are 16 three-fourths in 12.
What is the equation of the line in point-slope form that passes through the points (-1 7) and (-2 3)?
Points: (9, 1) and (4, 16) Slope: (1-16)/(9-4) = -3 Equation: y-1 = -3(x-9) => y = -3x+28 Equation: y-16 = -3(x-4) => y = -3x+28
Slope of 2x-3y equals 16?
2x-3y=16 Write this in standard form (y = mx+c), 3y = 2x-16 or y = 2/3x - 16/3 so the slope is 2/3
What does evaluate 16y plus 9 for y equals 3 mean?
Replace the y with a 3. 16 x 3 + 9 = 57
