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What is 16 equals the fraction of y 3?
do you mean 16 = y / 3 ?? if so, y = 48.
How is the square root of 16 related to the cube root of 16?
Suppose sqrt(16) = x and cuberoot(16) = y, then then x^2 = 16 = y^3 so that x^(2/3) = y x = y^(3/2).
Y equals 1 plus 3x and y equals 16-2x What is X and Y?
y = 1 + 3x y = 16 - 2x Because y = y, that means... 1 + 3x = 16 - 2x Solve for x... x = 3 Plug it back in to one of the original equations... Y = 1 + 3(3) = 10 So... x = 3 y = 10
What does 8y over y plus 2 plus 16 over y plus 2 equal?
8y/y + 2 + 16/y + 2 = 8 + 2 + 16/y +2 = 12 + 16/y = 4(3 + 4/y) or 4/y*(3y + 4)
X2 plus 4x plus y2-6y equals 3?
x2 + 4x + y2 - 6y = 3 You need to be more clear about your question: Are you trying to find the properties of the curve it defines? x2 + 4x + y2 - 6y = 3 ∴ x2 + 4x + 4 + y2 - 6y + 9 = 16 ∴ (x + 2)2 + (y - 3)2 = 42 ∴ This describes a circle with a radius of 4, and a center point of (-2, 3) Did you want to solve for y? (x + 2)2 + (y - 3)2 = 42 ∴ (y - 3)2 = 16 - (x + 2)2 ∴ y - 3 = ± [16 - (x + 2)2]1/2 ∴ y = 3 ± [16 - (x + 2)2]1/2 Did you want to solve for x? (x + 2)2 + (y - 3)2 = 42 ∴ (x + 2)2 = 16 - (y - 3)2 ∴ x + 2 = ± [16 - (y - 3)2]1/2 ∴ x = -2 ± [16 - (y - 3)2]1/2
