9,5,1 /861/852/843/771/762/753/744/663/654/555/ are all the whole number answers
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There are 15, and they are:1234 1235 1236 1245 1246 1256 1345 1346 1356 1456 2345 2346 2356 2456 3456.
The answer is 135. 15 times 9 equals 135 27 times 5 equals 135
7
There are 4 choices for the first digit (1, 2, 3, or 4) since zero cannot be the first digit in a four-digit number. For the second digit, there are 3 remaining choices, for the third digit there are 2 choices, and for the fourth digit, there is only 1 choice left. Therefore, the total number of four-digit numbers that can be formed using the digits 1, 2, 3, and 4 is 4 x 3 x 2 x 1 = 24.
6C4 = 6*5/(2*1) = 15
15
Oh, dude, you're hitting me with some math vibes here. So, if you have 6 digits to choose from to make a 4-digit combination, you can calculate that by using the formula for permutations: 6P4, which equals 360. So, like, you can make 360 different 4-digit combinations from those 6 digits. Math is wild, man.
There are 15, and they are:1234 1235 1236 1245 1246 1256 1345 1346 1356 1456 2345 2346 2356 2456 3456.
As the number has to start with 15, we have only 3 remaining digits to work with. There are 3 possible options for the first digit. Then out of each of these, 2 possible options for the second digit, and one option for the last. This means that in total there are 3x2x1 (6) possible combinations. These are: 15234 15243 15324 15342 15423 15432
There are infinite combinations that can make 3879
There are two combinations of numbers when multiplied together are equal to 15. 1 x 15 = 15 and 3 x 5 = 15.
The product of 12 times 15 is 180. This can be calculated by multiplying 12 by 15, as each digit in the first number is multiplied by each digit in the second number, and then adding the results together. In this case, 12 times 15 equals 180.
If you use them only once each, you can make 15 combinations. 1 with all four digits, 4 with 3 digits, 6 with 2 digits, and 4 with 1 digit. There is also a combination containing no digits making 16 = 24 combinations from 4 elements.
There are 15C3 = 15*14*13/(3*2*1) = 455 combinations, and I am NOT even going to try listing them.
The answer is 135. 15 times 9 equals 135 27 times 5 equals 135
It is: 6C4 = 15-------------I disagree with the first answer.Each of the four digits can be chosen in 6 ways: 6 x 6 x 6 x 6 = 64 = 1296
Six fifteens and a double pair royal equals 24.