class width is a width width is a width nothing as class width is a width dont be confuse
Frequency density= Frequency/Class width So shut ur mouth whoever is reading this!
The class interval.
Frequency Density multiplied by the class width
There is no requirement in the question that the classes should be of equal width. Consequently, class widths of 10, 10, 10, 10, 10 and 27 (or 30) will do the trick.
To calculate the frequency density we will simply divide the frequency by the class width.
class width is a width width is a width nothing as class width is a width dont be confuse
There is no correlation between class width and student achievement. Class width is arbitrary (there are rules of thumb for class width, and it depends on the range of the data).
Frequency density= Frequency/Class width So shut ur mouth whoever is reading this!
well to calculate the width of a classroom you have to measure the width of each wall and then add up all of the measurements you found out and then that will be the width of the classroom. i hope this helps :) :) :) :) :)
You can calculate the volume by multiplying height, width, and mass. Then, divide the mass by the density to find the volume. Finally, calculate the length by dividing the volume by the height and width.
To calculate volume simply do length x width x height
Multiply the height by the width
36 inch
This is not a question, it is an assignment. class Geo { public: virtual double area (void) const = 0; virtual ~Geo (void) {} // ... }; class Rect : public Geo { private: double m_width; double m_height; public: Rect (double width, double height): m_width (width), m_height (height) {} double area (void) const override { return m_width * m_height; } ~Rect (void) override {}; // ... }; class Sqr : public Rect { public: Sqr (double width): Rect {width, width} {} ~Sqr (void) override {} // ... };
Multiply the width times the height.
NONE