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Q: How do you find highest standard deviation in given number?

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A single number, such as 478912, always has a standard deviation of 0.

Yes.

standard deviation is the square roots of variance, a measure of spread or variability of data . it is given by (variance)^1/2

You cannot from the information provided.

idk about normal distribution but for Mean "M" = (overall sum of "x") / "n" frequency distribution: 'M' = Overall sum of (' x ' * ' f ') / overall sum of ( ' f ' ) M = Mean x = Mid Point f = frequiency n = number of variables ALL FOR STANDARD DEVIATION * * * * * A general Normal distribution is usually described in terms of its parameters, and given as N(mu, sigma2) where mu is the mean and sigma is the standard deviation. The STANDARD Normal distribution is the N(0, 1) distribution, that is, it has mean = 0 and variance (or standard deviation) = 1.

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A single number, such as 478912, always has a standard deviation of 0.

A single number, such as 478912, always has a standard deviation of 0.

Square the standard deviation and you will have the variance.

A standard deviation in statistics is the amount at which a large number of given values in a set might deviate from the average. A percentile deviation represents this deviation as a percentage of the range.

Yes.

standard deviation is the square roots of variance, a measure of spread or variability of data . it is given by (variance)^1/2

1.10

A standard deviation calculator allows the user to find the mean spread away from the mean in a statistical environment. Most users needing to find the standard deviation are in the statistics field. Usually, the data set will be given and must be typed into the calculator. The standard deviation calculator will then give the standard deviation of the data. In order to find the variance of the data, simply square the answer.

The mean and standard deviation do not, by themselves, provide enough information to calculate probability. You also need to know the distribution of the variable in question.

49.30179172 is the standard deviation and 52 is the mean.

1.6*s+mean and1.6*s and count numbers between them

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