6! = 720
There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.
If you want 4-digit numbers, there are 24 of them.
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
9
How many four digit combinations can be made from the number nine? Example, 1+1+2+5=9.
999-111=888 888 3 digit numbers can be made with numbers between 1 - 9
120
162
1
ten
1,956 different numbers can be made from 6 digits. You can calculate this by using the permutation function in a summation function, like this: Σ6k=1 6Pk = 6P1+6P2+...+6P5+6P6 What this does is calculate how many 1 digit numbers you can make from 6 digits, then how many 2 digit numbers can be made from 6 digits and adds the amounts together, then calculates how many 3 digit numbers can be made and adds that on as well etc.
2 Nope! definitely not 2.. The answer should be 126 I'm looking for the solution. Eg. Q. How many 4 digit numbers can be made from the digits 1-9 A. 9X8X7X6= 3024.
1
321 312 213 231 123 132 6 3 digit numbers.
59
total 6- 18,19,81,89,91,98
120 5-digit numbers can be made with the numbers 12345.