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Anonymous

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How many 3 digits combinations can be made from 1234567890?

To calculate the number of 3-digit combinations that can be made from the numbers 1-9, we can use the formula for permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the total number of options (10 in this case) and r is the number of digits in each combination (3 in this case). Therefore, the total number of 3-digit combinations that can be made from the numbers 1-9 is 10^3 = 1000.


How many 4 number combinations are there in the number 0 to10?

The number of combinations is 10C4 = 10*9*8*7/(4*3*2*1) = 210


How many 3 digit combinations can be made from 1 to 9?

All the numbers from 0 to 999 so 1000 numbers However if you mean only using each number once the answer is about 720 * * * * * No. The above answer refers to the number of permutations. Permutations are NOT the same as combinations as anyone who has studies any probability theory can tell you. The number of combinations is 9C3 = 9*8*7/3*2*1 = 84


How many 4 digit combination no repeated numbers?

Well, honey, if you want to know the number of 4-digit combinations with no repeated numbers, it's pretty simple. You start with 9 choices for the first digit (can't be 0), then 9 choices for the second digit (can't repeat the first), 8 choices for the third digit, and finally 7 choices for the fourth digit. Multiply those together and you get 4536 possible combinations. Easy peasy lemon squeezy!


How many combinations are there if there are 8 numbers and you have a 16 number combination?

Assuming that "number" means digits and that it is permutations (rather than combinations) that are required, the answer is 816 which is 281.475 trillion (approx).

Related Questions

How many combinations are there for a 8 digit number 1-8?

Using the eight digits, 1 - 8 ,-- There are 40,320 eight-digit permutations.-- There is 1 eight-digit combination.


How many combinations of 2 and 3 digit number using 4 and 8?

the answer is = first 2-digit number by using 48= 28,82 and in 3 digit is=282,228,822,822


How many three digit number combinations are there if you can not repeat a number?

there are 10 possibilities for the first spot, 9 for the second, 8 for the third 10x9x8=720 combinations


How many 2 number combinations are there in the numbers 1 to 9?

There are 9C2 = 9*8/(2*1) = 36 2-digit combinations.


How many six digit combinations are available from a 9 digit number?

That depends on how many of the digits are repeated. If no digits are repeated, you have 9 choices for the first digit, 8 choices for the second, etc.; for a total of 9 x 8 x 7 x 6 x 5 x 4.


How many different combinations are possible multiplying 8 different 7 digit numbers?

56 combinations. :)


How many different combinations of an 8 digit password using the same 8 digits?

1


How many 3 single digit combinations add up to 24 and what are they?

27


How many four digit numbers are possible which do not contain 3 or 6?

The answer is 3,584. The first digit of the four-digit number can be one of seven figures: 1,2,4,5,7,8 or 9 (if it is 0, then you don't have a four-digit number!) Each of the remaining digits can be one of eight figures: 1,2,4,5,7,8,9 or 0. The number of possible combinations is therefore 7 x 8 x 8 x 8 = 3,584.


How many 8 digit number are there in total?

The first 8 digit number is 10,000,000, the last is 99,999,999 which means there are 90,000,000 8 digit numbers


If using numbers 1 - 9 how many two digit combinations can be found?

-8


What are all the possible number combinations for 4 digit odd numbers for 7 5 4 and 8?

16