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If you mean how many different ways can you arrange six numbers, its 6! which is six factorial, I'm not just really happy about that.

Thats because there are six options for the first of the numbers, 5 for the second (because one has been removed), 4 for the third and so on.

And six factorial = 6 * 5 * 4 * 3 * 2 * 1

n! = 1 * 2 * 3 * ... * (n-2) * (n-1) * n

* * * * *

That is not correct. In a combination, the order of the numbers does not matter so that 123456 is the same as 135246 and so on.

What matters is how many numbers the six are being selected from. If the six are being selected from n different numbers, the number of combinations is

nC6 = n!/[6!(n-6)!] where n! is as defined above, and 0! = 1

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13y ago

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Q: How many combinations are there in 6 numbers?
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