16 if you include 0 starting
12 if not
That is not correct.
0123 is a 4-digit number = (n)
therefore n! = 4! = 1*2*3*4 = 24 (if 0 is included as I assume that is the question)
123 is a 3-digit number = (n)
Therefore n! = 3!= 1*2*3 = 6
With four digits (0, 1, 2, 3) and no repetition allowed, the number of possible combinations can be calculated using the permutation formula. Since the order matters, the number of permutations is 4! (4 factorial) which equals 4 x 3 x 2 x 1 = 24. Therefore, there are 24 possible number combinations with the digits 0, 1, 2, and 3.
Just 4: 123, 124, 134 and 234. The order of the numbers does not matter with combinations. If it does, then they are permutations, not combinations.
As there are 26 letters in the alphabet. You can calculate the number of combinations by multiplying 26x26x26, giving you the answer 17576.
4 of them. In a combination the order of the numbers does not matter.
if i got everything right, its 1000
It depends on whether the order of the numbers is important or not. For example, if 123456 is seen as a different code to 213456 then there are many more possible solutions.If the order is unimportant, the number of possible combinations is equal tobinomial coefficient(15,6) = 5005If the order is important, then the number of possible permutations is equal to15! = ~1.3x1012
Since a number can have infinitely many digits, there are infinitely many possible combinations.
35
There are infinitely many numbers and so infinitely many possible combinations.
2^n possible combinations
If repeats are allowed than an infinite number of combinations is possible.
There are countless possible liquid combinations, depending on the types of liquids you are considering (water, juice, alcohol, etc.) and how many you want to mix together. The number of combinations would be exponential, as each additional liquid increases the number of possible combinations exponentially.
61
The number of combinations - not to be confused with the number of permutations - is 2*21 = 42.
Just 4: 123, 124, 134 and 234. The order of the numbers does not matter with combinations. If it does, then they are permutations, not combinations.
There's a lot of possible answers to this one. Is it that each digit can be 0 through 9? In which case you get every number from 0000 to 9999 which is 10,000 possible answers. Or is it that each number can only be used once? In which case, the first possible answer is 0123 and the last possible answer is 9876. That still leaves 5,040 possible answers, which is way too many to just list. Here's the first 15 though to get you started. 0123 0124 0125 0126 0127 0128 0129 0132 0134 0135 0136 0137 0138 0139 0142
As there are 26 letters in the alphabet. You can calculate the number of combinations by multiplying 26x26x26, giving you the answer 17576.
There are only five combinations: 1234, 1235, 1245, 1345 and 2345.