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How many permutations of the letters in the word Louisiana are there?
The number of permutations of the letters in the word LOUISIANA is 9 factorial or 362,880. However, since the letters I and A are each repeated once, you need to divide that by 4 to determine the number of distinct permutations, giving you 90,720.
How many permutations are possible of the word yard?
Imagine you have four empty buckets in which to put any of the four letters Y, A, R, D into. At first you have four letters that can be placed in any of the four empty buckets. Once you've placed a letter in a bucket you only have three letters and three empty buckets to choose from. And so on... So there are 4x3x2x1 = 24 permutations of the word YARD.
How many ways can you arrange the letters in the word faith?
Once...its true!
How many 3 digit combinations can be made from 1 to 9?
All the numbers from 0 to 999 so 1000 numbers However if you mean only using each number once the answer is about 720 * * * * * No. The above answer refers to the number of permutations. Permutations are NOT the same as combinations as anyone who has studies any probability theory can tell you. The number of combinations is 9C3 = 9*8*7/3*2*1 = 84
How many meaningful English words can be formed with the letters ILKE using each letter only once in each word?
At least three.
How many permutations of the letters in the word Louisiana are there?
The number of permutations of the letters in the word LOUISIANA is 9 factorial or 362,880. However, since the letters I and A are each repeated once, you need to divide that by 4 to determine the number of distinct permutations, giving you 90,720.
How many distinguishable 5-letter combinations are possible of the letters of the word tight?
Normally, there would be 5!=120 different permutations* of five letters. Since two of the letters are the same, we can each of these permutations will be duplicated once (with the matching letters switched). So there are only half as many, or 60 permutations.* (the correct terminology is "permutation". "combination" means something else.)
How many different 4-letter permutations can be formed from the letters in the word DECAGON?
The word "DECAGON" has 7 letters, with the letter "A" appearing once, "C" appearing once, "D" appearing once, "E" appearing once, "G" appearing once, "N" appearing once, and "O" appearing once. To find the number of different 4-letter permutations, we need to consider combinations of these letters. Since all letters are unique, the number of 4-letter permutations is calculated using the formula for permutations of n distinct objects taken r at a time: ( P(n, r) = \frac{n!}{(n-r)!} ). Here, ( n = 7 ) and ( r = 4 ), so the number of permutations is ( P(7, 4) = \frac{7!}{(7-4)!} = \frac{7!}{3!} = 7 \times 6 \times 5 \times 4 = 840 ). Thus, there are 840 different 4-letter permutations that can be formed from the letters in "DECAGON."
How many permutations are there word mathematics?
The number of permutations of the letters MATHEMATICS is 11 factorial or 39,916,800. However, since the M is repeated once you must divide by 2. You must also divide by 2 because the A is repeated once. And again for the T. This results in an overall distinct permutation count of 4,989,600.
How many different arrangements of 7 letters can be formed from the letters in the word ALGEBRA?
The number of 7 letter permutations of the word ALGEBRA is the same as the number of permutation of 7 things taken 7 at a time, which is 5040. However, since the letter A is duplicated once, you have to divide by 2 in order to find out the number of distinct permutations, which is 2520.
How many different 5 letter arrangements can be formed from the letters in the word Danny?
The number of 5 letter arrangements of the letters in the word DANNY is the same as the number of permutations of 5 things taken 5 at a time, which is 120. However, since the letter N is repeated once, the number of distinct permutations is one half of that, or 60.
How many permutations are possible of the word yard?
Imagine you have four empty buckets in which to put any of the four letters Y, A, R, D into. At first you have four letters that can be placed in any of the four empty buckets. Once you've placed a letter in a bucket you only have three letters and three empty buckets to choose from. And so on... So there are 4x3x2x1 = 24 permutations of the word YARD.
What is the number of distinguishable permutations of the letters in the word EFFECTIVE?
The number of permutations of the letters EFFECTIVE is 9 factorial or 362,880. Since the letter E is repeated twice we need to divide that by 4, to get 90,720. Since the letter F is repeated once we need to divide that by 2, to get 45,360.
How many distinguishable permutations can be made from the letters in the word gallipolis?
In the word "gallipolis"there are 10 letters (n =10)."l" appears 3 times (n1 =3)."i" appears 2 times (n2 =2).And 5 letters appear once (n3 =1, n4 =1, n5 =1, n6 =1, n7 =1)The number of permutations that can be made with these 10 letters is;P =n!/(n1!n2!n3!n4!n5!n6!n7!) =10!/(3!∙2!∙1!∙1!∙1!∙1!∙1!) =302 400
How many mathematical word are there?
The number of permutations of the letters MATHEMATICS is 11 factorial or 39,916,800. However, since the M is repeated once you must divide by 2. You must also divide by 2 because the A is repeated once. And again for the T. This results in an overall distinct permutation count of 4,989,600.
How many different combinations are possible if a coin is tossed once and a number cube is tossed twice?
There are 72 permutations of two dice and one coin.
How many different arrangements of the letters in the word GOAL are there if all the letters are used exactly once?
There are 24.
