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How many distinguishable 5-letter combinations are possible of the letters of the word tight?
Normally, there would be 5!=120 different permutations* of five letters. Since two of the letters are the same, we can each of these permutations will be duplicated once (with the matching letters switched). So there are only half as many, or 60 permutations.
* (the correct terminology is "permutation". "combination" means something else.)
What else can I help you with?
How many distinguishable permutations of letters are possible in the word class?
120?
How many possible combinations are there for 4 letters?
24
How many 9 letter combinations using 26 alphabet letters?
3,124,550 possible combinations
How many possible combinations of 3 letters can you make?
As there are 26 letters in the alphabet. You can calculate the number of combinations by multiplying 26x26x26, giving you the answer 17576.
How many combinations of two letters are possible from the letters J T S L and G?
10
What are all the possible 11 digit combinations of letters A-Z and numbers 0-9 combined?
There are 36 possible characters (26 letters + 10 numbers) that can be used in each position of the 11-digit combination. Therefore, the total number of possible combinations is 36^11, which is approximately 7.52 x 10^17. This means there are over 750 quadrillion possible 11-digit combinations of letters A-Z and numbers 0-9 when combined.
How many possible combinations could be constructed using 3 letters and 3 numbers for a license plate?
To calculate the total number of possible combinations for a license plate using 3 letters and 3 numbers, we need to multiply the number of options for each character position. For letters, there are 26 options (A-Z), and for numbers, there are 10 options (0-9). Therefore, the total number of combinations can be calculated as 26 (letters) * 26 (letters) * 26 (letters) * 10 (numbers) * 10 (numbers) * 10 (numbers) = 17,576,000 possible combinations.
How many distinguishable permutations of the letters CAT?
cat
How may distinguishable permutations are possible with all the letters of the word ellises?
We can clearly observe that the word "ellises" has 7 letters and three pairs of letters are getting repeated that are 'e','l' and 's'. So, Number of distinguishable permutations = 7!/(2!2!2!) = 7 x 6 x 5 x 3 = 630.
How many possible alpha numeric combinations using letters and numbers for 8 characters?
it is 26
How many distinguishable permutations of letters are in the word queue?
three
How many distinguishable permutations are there in the word letters?
7 factorial
