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How many possible outcomes would there be if four coins were tossed once?
Wiki User
∙ 13y ago
there could be five possible outcomes: t= tails h= heads
t t t t 4 tails
t t t h 3 tails 1 head
t t h h 2 tails 2 heads
t h h h 1 tail 3 heads
h h h h 4 heads
Wiki User
∙ 13y ago
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Two coins and one six sided cube are tossed together What is the probability of getting 2 heads and a four?
Probability is defined as the number of ways an outcome can occur divided by the number of possible outcomes. For the coins, there are 4 outcomes (HH, HT, TH, TT). On the cube, there are 6 possible outcomes. The total number of outcomes is then 4*6 = 24. Since there is only 1 way to obtain HH, look at the cube outcomes. With the HH outcome, the cube would need to fall on a 4. So, there is only 1 way a HH4 can occur. Therefore the probability of getting 2 heads and a four is 1/24 or 0.04167.
What is the probability of getting 2 tails if 3 fair coins are tossed?
There are eight possible outcomes: HHH, HHT, HTT, HTH, TTT, TTH, THH, THT. Of these, 3 contain two tails: HTT, TTH, and THT and the probability of getting two tails is 3/8. If the question were 'getting at least two tails' then TTT would need to be included for a probability of 4/8 or 0.5.
If four coins are tossed what is the probability of getting three heads and one tail?
With 4 coins you have 24 (16) possibilities. If we wanted a specific coin to land 'tails' while the others landed 'heads' we would have one possibilty out of 16. Since we don't care which of the coins lands 'tails,' we have four chances in 16 or a 25 percent chance.
If you toss 4 coins what is the probability of getting two heads and two tails?
When tossing a coin, there are 2 distinct possibilities: heads or tails. When tossing 4 coins, there are 2 x 2 x 2 x 2 = 16 possible outcomes. To determine the number of outcomes that will result in 2 heads and 2 tails the formula would be n!/(h!)(n-h)! where n = number of coinsand h = number of heads. In this case the number of different ways you can get 2 heads and 2 tails would be4!/(2! x 2!) = 6 Let's verify the number of different ways you can get two heads and two tails: H H T TH T T HH T H T T T H HT H H TT H T H These are the six different ways to get two heads and two tails with four coins. To find the probability, you divide 6 by the total number of possible outcomes (16) and you would get 6/16 = 3/8. The probability of tossing 4 coins and getting two heads and two tails is 3/8 or 0.375
What are two requirements for a discrete probability distribution?
Not sure about only two requirements. I would say all of the following:there is a finite (or countably infinite) number of mutually exclusive outcomes possible,the probability of each outcome is a number between 0 and 1,the sum of the probabilities over all possible outcomes is 1.The Poisson distribution, for example, is countably infinite.
How many outcomes are possible if 10 coins are tossed together?
I believe there would be 11 possible outcomes!
How many possible outcomes would be if three coins were tossed once?
There are eight (8).
How many possible outcomes would there be if three coins were each tossed onces?
Eight of them.
How many possible outcomes would there be if thirty two coins were tossed once?
Since each coin would have the outcome with Heads and Tails: Then among the 32 coins, we can have the possible outcomes from no Heads, 1 Head, 2 Heads, ....... , 31 Heads, 32 Heads. Therefore we would have 33 outcomes.
How many possible outcomes would there be if three coins were tossed up three times?
9, you just have to multiply for problems like this
How many combinations of one head and one tail would you expect if two coins were tossed together forty times?
The theoretical probability of HT or TH when two coins are tossed is 1/2 . (All possible outcomes are HH,TT,HT,TH). This means that when we run the experiment repeatedly we expect to get the desired result 1/2 of the time. Since you intend to toss the coins 40 times, 20 are expected.
How many possible outcomes would there be if three coins were tossed once?
Given that x is cross and o is head the possible outcomes would be: x-x-x o-x-x x-o-x x-x-o o-o-x o-x-o x-o-o o-o-o Thence there are 8 possible outcomes. Assumptions: 1) Each coin ends up head or tail (never on its side) 2) The coins are distinctinguishable (maybe a penny dime and quarter). If three identical perfectly balanced pennies are tossed at the same time there are 4 outcomes (all heads or all tails 1/8 of the time each and just one or just 2 heads 3/8 of the time each)
Two coins and one six sided cube are tossed together What is the probability of getting 2 heads and a four?
Probability is defined as the number of ways an outcome can occur divided by the number of possible outcomes. For the coins, there are 4 outcomes (HH, HT, TH, TT). On the cube, there are 6 possible outcomes. The total number of outcomes is then 4*6 = 24. Since there is only 1 way to obtain HH, look at the cube outcomes. With the HH outcome, the cube would need to fall on a 4. So, there is only 1 way a HH4 can occur. Therefore the probability of getting 2 heads and a four is 1/24 or 0.04167.
Two coins are flipped and a die is rolled how many possible outcomes are there?
Each coin can land in two ways.The die has 6 possible outcomes.So there are 2 x 2 x 6 = 24 possible outcomes for the whole experiment.Note that I am assuming the coins can be told apart - say the first coin and 2nd coin and that H and then T is different that T and then H. If not, then there are only be three outcomes for the coins-- 2 heads, 1 head or no heads and the total number of outcomes would be 3 X 6 = 18.
How many different outcomes would be possible if you rolled a single die and then two coins?
The single die can land in 6 different ways. For each of those . . . The first coin can land in 2 different ways. For each of those . . . The second coin can land in 2 different ways. Total number of different possible outcomes = (6 x 2 x 2) = 24 IF the coins have different colors so that you can tell them apart. If you can't tell the coins apart, then there are only 12 different outcomes.
How many possible outcomes would there be if a coin is tossed?
2, there could only be two outcomes. Heads or tails As in any experiment you need to define a valid toss. So if you are examining the number of heads and tails you would limit the outcomes to these two states. However, in a real world experiment there may be a condition where the coin landed on a uneven surface and was tilted in some way. The number of tilted ways is infinite. You could also have the coin land on its edge which is unlikely but possible.
What is the probability of getting 2 tails if 3 fair coins are tossed?
There are eight possible outcomes: HHH, HHT, HTT, HTH, TTT, TTH, THH, THT. Of these, 3 contain two tails: HTT, TTH, and THT and the probability of getting two tails is 3/8. If the question were 'getting at least two tails' then TTT would need to be included for a probability of 4/8 or 0.5.
