Given that x is cross and o is head the possible outcomes would be:
x-x-x
o-x-x
x-o-x
x-x-o
o-o-x
o-x-o
x-o-o
o-o-o
Thence there are 8 possible outcomes. Assumptions: 1) Each coin ends up head or tail (never on its side) 2) The coins are distinctinguishable (maybe a penny dime and quarter). If three identical perfectly balanced pennies are tossed at the same time there are 4 outcomes (all heads or all tails 1/8 of the time each and just one or just 2 heads 3/8 of the time each)
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There are eight (8).
9, you just have to multiply for problems like this
three heads two head, one tails one heads, two tails three tails
Each coin can land in two ways.The die has 6 possible outcomes.So there are 2 x 2 x 6 = 24 possible outcomes for the whole experiment.Note that I am assuming the coins can be told apart - say the first coin and 2nd coin and that H and then T is different that T and then H. If not, then there are only be three outcomes for the coins-- 2 heads, 1 head or no heads and the total number of outcomes would be 3 X 6 = 18.
C(8,3) = 56